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FinnZ [79.3K]
3 years ago
13

Factor completely 3x^2+7x-6

Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0
I find the following method easiest to factor this equation.

1. First, fill in what you know would be the factors for the first value, 3x^2.  The number 3 only has 2 factors: 3 and 1. Therefore, we know the first values are:

(3x _____)(x_____)

2. Next, figure out what the possible factors for the last value would be (-6). The following combinations are possible:
2 and -3 OR -3 and 2
-2 and 3 OR 3 and -2
-1 and 6  OR 6 and -1
1 and -6 OR -6 and 1

3. Plug in the combinations into step 1 and see which gives you the correct answer:
<span>(3x + 2)(x - 3) = 3x^2 - 7x - 6 --> no
</span>(3x - 3)(x + 2<span>) = 3x^2 + 3x - 6 --> no
</span>(3x - 2)(x + 3) = 3x^2 + <span>7x - 6 --> YES</span>
vaieri [72.5K]3 years ago
6 0
Factor \ 3x^2+7x-6 

1. \ Multiply \ 3 \ by \ -6, \ which \ is \ -18.

2. \ Ask: \ Which \ two \ numbers \ add  \ up \ to \ 7 \ and  \ multiply \ to -18?

Answer: \ 9  \ and \ -2

4. \ Rewrite \ 7x \ as \ the \ sum \ of \ 9x \ and  \ -2x:

&#10;3x^2+9x-2x-6&#10; &#10;&#10; 
 
&#10;3x(x+3)-2(x+3)&#10; &#10;  Factor \ out \ common \ terms \ in \ the \ first \ two \ terms,  then \ in \ the \ last two \ terms 

(x+3)(3x-2) Factor \ out \ the \ common \ term  \ x+3

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