Liquid silver is less dense than solid silver, so the solid silver would sink
Answer: The answer is 185 Pm
<h3>
Answer:</h3>
2 × 10²⁴ atoms Co
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
4 mol Co (Cobalt)
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
![\displaystyle 4 \ mol \ Co(\frac{6.022 \cdot 10^{23} \ atoms \ Co}{1 \ mol \ Co})](https://tex.z-dn.net/?f=%5Cdisplaystyle%204%20%5C%20mol%20%5C%20Co%28%5Cfrac%7B6.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20Co%7D%7B1%20%5C%20mol%20%5C%20Co%7D%29)
- Multiply/Divide:
![\displaystyle 2.4088 \cdot 10^{24} \ atoms \ Co](https://tex.z-dn.net/?f=%5Cdisplaystyle%202.4088%20%5Ccdot%2010%5E%7B24%7D%20%5C%20atoms%20%5C%20Co)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 1 sig fig.</em>
2.4088 × 10²⁴ atoms Co ≈ 2 × 10²⁴ atoms Co