What is the wavelength of light emitted between the 3 rd and 1 st energy levels? 121.5 nm 94.5 nm 102.5 nm 1875 nm
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The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.
<u>Explanation:</u>
Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.
As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.
Hence,
Thus, the molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.
2,02g ------- 6,02×10²³
5,01×10⁴g --- x
N₂ + 3H₂ ⇒ 2NH₃
1mol : 3mol : 2mol
18,06×10²³ : 12,04×10²³
14,93×10²⁷ : y
5,01×10⁴g --- x
N₂ + 3H₂ ⇒ 2NH₃
1mol : 3mol : 2mol
18,06×10²³ : 12,04×10²³
14,93×10²⁷ : y