Answer:
T₂ = 51826.1 K
Explanation:
Given data:
Initial Volume = 2.3 L
Final volume = 400 L
Initial temperature = 25 °C (25+ 273 = 298 K)
Final temperature = ?
Solution:
V₁/T₁ = V₂/T₂
T₂ = V₂ T₁/V₁
T₂ = 400 L . 298 K / 2.3 L
T₂ = 119200 K. L / 2.3 L
T₂ = 51826.1 K
<span>Iron phosphate when in an acid solution ionizes or dissociates into ions. The ions are the Iron (III) and the HPO4^2-. The net ionic equation should be as follows:
FePO4(s)+H3O +(aq)⇌Fe^3+(aq)+HPO4^2−(aq)+H2O(l)</span>
Answer:
0.1832 moles of ethyl acetate (
)
Explanation:
1. Find the balanced chemical equation:
In the production of ethyl acetate, the acetic acid 
reacts with ethanol to produce ethyl acetate and water, that is:
2. Find the theoretical maximum moles of ethyl acetate :
As the problem says that the acetic acid is the limiting reagent, use stoichiometry to find the moles of ethyl acetate produced:
