Find the perimeter of the shaded region. 1.58 ft 2.38 ft 3.90 ft 4.24 ft

What are the greatest common factor of 20x76 and 8x92?

adelina 88 [10]

Gcf of 20 time 76 is 4

6 0

2 years ago

-5 + 8 • -7 help lols

iris [78.8K]

Answer:

Step-by-step explanation:

-5 + (8 x -7)

using PEMDAS, (8 x -7) = -56

so -5 + -56 = -61

5 0

2 years ago

CAN SOMEONE PLEASE HELP!!!!!!!

AveGali [126]

Answer:

-11

Step-by-step explanation:

Add all the negative numbers.

Hope this helps!

4 0

3 years ago

Read 2 more answers

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is a separable differential equation. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$

Therefore,

$\frac{1}{r} \ln |rA+P| = t+c$

Multiply both sides by $r.$

$\ln |rA+P| = rt+c_1, \quad c_1 := rc$

By taking exponents, we obtain

$e^{\ln |rA+P|} = e^{rt+c_1} \implies |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}$

Isolate $A$ .

$rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}$

Since $A = 0$ when $t=0$ , we obtain an initial condition $A(0) = 0$ .

We can use it to find the numeric value of the constant $c$ .

Substituting $0$ for $A$ and $t$ in the equation gives

$0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P$

Therefore, the solution of the given differential equation is

$A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)$

4 0

2 years ago

HELP! After finding area explain the reasoning you used to find the area and I’ll give brainliest!

UkoKoshka [18]

Answer:

The answer is 180 yds squared.

Step-by-step explanation:

Segment the areas. One area has the measurements 5 and 6. Then the other one has measurements 15 and 10. This means you get 150 + 30. The answer is 180 yds squared.

4 0

2 years ago