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prisoha [69]
3 years ago
10

Write 45 as a product of the gcf and another number

Mathematics
1 answer:
Maru [420]3 years ago
8 0
The answer might be 45 x 1, because 45 is the greatest factor of 45.
 If you want to know why tell me
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antoniya [11.8K]
4/6 

4/6 = 2/3
4/6 = 8/12

Answer : 2/3 and 8/12
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A patio has an area of 50. the width is 3/4 of the length. what is the length?
Zielflug [23.3K]

Answer:

37.5

Step-by-step explanation:

12.5x3=37.5

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3 years ago
Shreya and beth each improved their yards by planting rose bushes and ornamental grass. They brought their supplies from the sam
frutty [35]

Answer:

  • <u><em>The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.</em></u>

Explanation:

Name the variables and build a system of two equations with two unknowns.

<u>1. Variable r</u>: cost of one rose bush

<u>2. Variable g</u>: cost of one bunch of ornamental grass.

<u>3. First equation</u>:

  • Shreya spent $68 on 4 rose bushes and 4 bunches of ornamental grass.

        4r + 4g = 68

<u>4. Second equation</u>:

  • Beth spent $115 on 11 rose bushes and 2 bunches of ornaments grass.

  • 11r + 2g = 115

<u>5. System of equations</u>:

  • 4r + 4 g = 68     equation 1
  • 11r + 2g = 115     equation 2

<u>6. Solve the system</u>

a) Divide the equation 1 by 2:

  • 2r + 2g  =  34     equation 1a
  • 11r + 2g = 115     equation 2

b) Subtract equation 1a from equation 2:

  • 11r - 2r = 115 - 34
  • 9r = 81
  • r = 81 / 9
  • r = 9

c) Substitute the value of r into the equation 1a:

  • 2(9) + 2g = 34
  • 9 + g = 17
  • g = 17 - 9
  • g = 8

<u>7. Conclusion</u>:

The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.

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Step-by-step explanation:

Just move the number by the log above the equation

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A hollow metal sphere of radius 5 cm is charged such that the potential on its surface is 10 volts. The potential at the centre
kap26 [50]
In your problem about the finding the potential voltage at the center of the sphere where as its radius is 5cm is charge such that the potential of its surface is 10volts. So the possible answer to this is also 10 volts, because the potential in the center and in the surface of the sphere is constant and the same.
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