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nika2105 [10]
2 years ago
10

Near the surface of the Earth, objects in free fall (but not terminal velocity) experience

Physics
2 answers:
FromTheMoon [43]2 years ago
6 0
<h2>Answer:</h2>

<u>Near the surface of the Earth, objects in free fall experience </u><u>maximum velocity</u>

<h2>Explanation:</h2>

The acceleration is constant and equal to the gravitational acceleration g which is 9.8 meters per square second at sea level on the Earth. When an object is moving upward its velocity is minimum at the top level and when it comes back to the surface of the earth its velocity increases. And near the surface of the Earth, objects in free fall experience maximum velocity

daser333 [38]2 years ago
3 0

Answer:

constant acceleration

Explanation:

An object is said to be in free fall when only one force is acting on it: the force of gravity, which pushes the object towards the ground.

Newton's second law states that the resultant of the forces acting on an object is equal to the product between the mass of the object (m) and its acceleration:

\sum F =ma (1)

for an object in free fall, there is only one force, the force of gravity:

F=mg

where g = 9.8 m/s^2 is the gravitational acceleration. Substituting this into (1), we have

mg=ma

and so

a=g

which means that the object is moving at constant acceleration downward, with acceleration equal to g = 9.8 m/s^2.

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Dafna11 [192]
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3 0
3 years ago
A rod of length 35.50 cm has linear density (mass per length) given by λ = 50.0 + 23.0x where x is the distance from one end, an
hram777 [196]

Answer:

(a)20.65g

(b)0.19m

Explanation:

(a) The total mass would be it's mass per length multiplied by the total lenght

0.355(50 + 23*0.355) = 20.65 g

(b) The center of mass would be at point c where the mass on the left and on the right of c is the same

Hence the mass on the left side would be half of its total mass which is 20.65/2 = 10.32 g

c(50 + 23c) = 10.32

23c^2 + 50c - 10.32 = 0

c \approx 0.19m

7 0
3 years ago
A ball is thrown with a speed of 20 m/s at an angle of 40o above the horizontal from the top of a 22-m tall building.
MrRissso [65]

Answer:

(a). The distance is  49.79 m.

(b). The speed of the ball is 24.39 m/s.

Explanation:

Given that,

Speed = 20 m/s

Angle = 40°

Height = 22 m

Time = 3.25 sec

(a). We need to calculate the distance

Using formula of distance

d=u\cos\theta\times t

Put the value into the formula

d=20\cos40\times3.25

d=49.79\ m

(b). We need to calculate the horizontal velocity

Using formula of velocity

v_{x}=u\cos\theta

Put the value into the formula

v_{x}=20\times\cos40

v_{x}=15.3\ m/s

We need to calculate the vertical velocity

Using equation of motion

v_{y}=u\sin\theta-gt

Put the value into the formula

v_{y}=20\sin40-9.8\times3.25

v_{y}=-19\ m/s

Negative sign shows the opposite direction.

We need to calculate the speed of ball

Using formula of speed

v=\sqrt{v_{x}^2+v_{y}^2}

v=\sqrt{(15.3)^2+(19)^2}

v=24.39\ m/s

Hence, (a). The distance is  49.79 m.

(b). The speed of the ball is 24.39 m/s.

4 0
2 years ago
Explain at least 3 primary and secondary online sources of data<br>​
Slav-nsk [51]

Answer And Explanation:

Primary sources of online data could be blog posts, twitter posts, and vlogs because the person producing forms of work is giving first-person account of his experience.

Secondary sources online data could be articles, news, and documentaries because people have gathered several primary sources to build their case that they are making.

Hope this is clear, and good luck with studies :)

7 0
3 years ago
I will give the Branliest!!! In which body of water can you see your reflected image better, a pond or an ocean? Why? (Please ex
GREYUIT [131]

Answer:

I would say a pond

Explanation:

A pond is more still than an ocean, therefore you could see your reflection better

4 0
2 years ago
Read 2 more answers
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