Answer:
please give me brainlist and follow
Explanation:
Yes if the body is travelling with uniform speed in a circular track its speed remains the same but the velocity is non-uniform as the direction of the body is changing every time.
1 MHz --- 1 000 000 Hz
99.5 MHz --- x
x = 99 500 000 Hz = 99,5x10^6 Hz
v = λ . f
c = λ . f
3x10^8 = λ . 99,5x10^6
λ = 3x10^8 / 99,5x10^6
λ ≈ 0,0302x10^2
<em>λ ≈ 3,02 m</em>
i think is the letter (B), isn't it?
Answer:
C. At the bottom of the circle.
Explanation:
Lets take
Radius of the circle = r
Mass = m
Tension = T
Angular speed = ω
The radial acceleration towards = a
a= ω² r
Weight due to gravity = mg
<h3>At the bottom condition</h3>
T - m g = m a
T = m ω² r + m g
<h3>At the top condition</h3>
T + m g = m a
T= m ω² r -m g
From above equation we can say that tension is grater when ball at bottom of the vertical circle.
Therefore the answer is C.
C. At the bottom of the circle.
thirty one and eight over se
venteen kilogram