Answer:
(B) False
Explanation:
The visible light and the x-rays are part of the electromagnetic spectrum, all in the spectrum travel in the vacuum at the same speed, at the speed of light (c = 299,792,458 m/s ). If the visible light ant the x-rays are traveling inside a medium, their velocity will change due to the properties of the medium but in the vacuum, their speed is the same.
13.06m
Explanation:
Given parameters:
initial velocity u = 0
final velocity v = 16m/s
Unknown;
height of the hill = ?
Solution:
We are going to apply one of the laws of motion to solve this problem;
V² = U² + 2gH
where V is the final velocity
U is the initial velocity
g is the acceleration due to gravity = 9.8m/s²
H is the height
since initial velocity is zero;
V² = 2gH
To find the height;
H = 
H =
= 13.06m
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The correct option is B.
There were 4 treatment conditions compared in the experiment.
F ratio plays an essential role in performing a particular dataset of ANOVA. F ratio is particularly a ratio which is obtained by the between-group variance or it is also called MSB and also within-group variance known as MSW. Any F-ratio which is computed is compared with the critical F-ratios from the table as it will check out if there are any variations available between the groups or not.
The researcher reports an F-ratio where the degrees of freedom = 3, 36.
F-ratio is obtained by the calculation of dividing the Mean squared errors because of the treatment by the Mean squared error which occurs due to error.
For the particular case, the researcher reports an F-ratio having degrees of freedom = 3, 36. It is indicating that the treatments are being distributed with degrees of freedom which is 3 and specified errors are distributed with degrees of freedom which is 36.
Let the treatments which were involved in the study can be denoted by k.
Let the total number of individuals involved in the study can be taken as N.
Then, the treatments will be having degrees of freedom as,
= k-1
3=k-1
k=3+1=4
Therefore, the required treatment condition number that was compared is 4.
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If the field strength between the plates is 9 volts per cm, then over a path of 1/2cm parallel to the field, the potential changes by (1/2) x (9 volts) = 4.5 volts.