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astraxan [27]
4 years ago
8

A machine part has the shape of a solid uniform sphere of mass 225 g and diameter 3.00 cm. It is spinning about a frictionless a

xle through its center, but at one point on its equator it is scraping against metal, resulting in a friction force of 0.0200 N at that point.
(a) Find its angular acceleration.
(b) How long will it take to decrease its rotational speed by 22.5 rad/s?
Physics
1 answer:
maw [93]4 years ago
6 0

Answer: a) angular acceleration(alpha)=-14.8rad/s^2

b) time taken (t) = 1.52s

Explanation:

What we are given

Mass of the solid sphere m =225g = 0.225kg

Diameter D = 3.00cm = 0.0300m

Radius = D/2 = 0.01500m

Frictional Force = 0.0200N

a) to determine the angular acceleration, we first calculate the torque, then moment of inertia, before the angular acceleration.

Torque = -fr

= - (0.0200)(0.01500)

=-3.00X10^-4Nm

Moment of inertia I

= 2/5mr^2

=2/5(0.225)(0.01500)^2

=2.025X10^-5kgm^2

Angular acceleration (alpha)= torque/moment of inertia (I)

= -3.00X10^-4Nm/2.025X10^-5kgm^2

=-14.8rad/s^2

b) time taken (∆t) = w/alpha

w= -22.5rad/s

Angular acceleration (alpha) = -14.8rad/s^2

∆t = -22.5/-14.8

= -1.52s

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Answer:

(B) False

Explanation:

The visible light and the x-rays are part of the electromagnetic spectrum, all in the spectrum travel in the vacuum at the same speed, at the speed of light (c = 299,792,458 m/s ). If the visible light ant the x-rays are traveling inside a medium, their velocity will change due to the properties of the medium but in the vacuum, their speed is the same.

3 0
4 years ago
a girl rides a sled down a frozen hill. she starts from rest at the top of the hill and reaches a speed of 16 m/s at the bottom
Zolol [24]

13.06m

Explanation:

Given parameters:

initial velocity u = 0

final velocity v = 16m/s

Unknown;

height of the hill = ?

Solution:

We are going to apply one of the laws of motion to solve this problem;

    V² = U² + 2gH

where V is the final velocity

           U is the initial velocity

           g is the acceleration due to gravity = 9.8m/s²

           H is the height

since initial velocity is zero;

          V² = 2gH

   To find the height;

             H = \frac{V^{2g} }{y}

   

              H = \frac{16^{2} }{2 x 9.8} = 13.06m

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5 0
3 years ago
A researcher reports an f-ratio with df = 3, 36 for an independent-measures experiment. how many treatment conditions were compa
user100 [1]

The correct option is B.

There were 4 treatment conditions compared in the experiment.

F ratio plays an essential role in performing a particular dataset of ANOVA. F ratio is particularly a ratio which is obtained by the between-group variance or it is also called MSB and also within-group variance known as MSW. Any  F-ratio which is computed is compared with the critical F-ratios from the table as it will check out if there are any variations available between the groups or not.

The researcher reports an F-ratio where the degrees of freedom = 3, 36.

F-ratio is obtained by the calculation of dividing the Mean squared errors because of the treatment by the Mean squared error which occurs due to error.

For the particular case, the researcher reports an F-ratio having degrees of freedom = 3, 36. It is indicating that the treatments are being distributed with degrees of freedom which is 3 and specified errors are distributed with degrees of freedom which is 36.

Let the treatments which were involved in the study can be denoted by k.

Let the total number of individuals involved in the study can be taken as N.

Then, the  treatments will be having  degrees of freedom as,

df_{treatments} = k-1

3=k-1

k=3+1=4

Therefore, the required treatment condition number that was compared is 4.

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1 pound

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