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Georgia [21]
3 years ago
14

When The appearance of a system changes does the mass of the system also change why why not

Chemistry
2 answers:
Dahasolnce [82]3 years ago
8 0

Your question has been heard loud and clear.

Well , if youre talking about chemistry , then yes youre right , Appearance and mass are totally different concepts , appearance of any substance only depends on how the surfaces absorb and relfect light. Mass , well it is constant for a system and will never change , appearance of a system may change but not because of mass.

Thank you

seropon [69]3 years ago
5 0
No, because the appearance has nothing to do with system as well as the fact that appearance is only how it looks

(Btw, that toga picture is like... ughhhh!) hope this helps you ♥︎☀︎☁︎♨︎

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The melting point of table salt is 801 degrees C. Is this a physical or chemical property?
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Melting point is a physical property 
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3 years ago
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A sample of gas occupies 10.0 l at 100.0 torr and 27.0
disa [49]
The pressure  of a sample  of a gas if the temperature  is changed  to 127  c  while  the volume  remains  constant   is calculated  using gay lussac law formula

that is P1/T1 = P2/V2
P1 = 100 torr
T1 = 27+273 = 300 k
T2 =127 +273 =400 k
P2=?

by  making P2 the subject of the formula
P2=T2P1/T1

=100  x 400/300 = 133.3 torr

5 0
4 years ago
What is the concentration of a solution that is 0.25 moles of HCL added to 3.00L of water?
Lina20 [59]

Answer: 0.08 M

Explanation:

\text{molarity}=\frac{\text{moles of solute}}{\text{liters of solution}}\\\\\text{molarity}=\frac{0.25}{3.00}\\\\\text{molarity}=\boxed{0.08 \text{ M}}

3 0
2 years ago
Which of the following is not a correct chemical equation for a double displacement reaction?
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i just took the test the answer is B

4 0
3 years ago
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An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f
Dima020 [189]

The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

  • Mass of carbon, C:

\frac{32.18}{100}\times 223.94 = 72.06 g

  • Mass of hydrogen, H:

\frac{4.5}{100}\times 223.94 = 10.08 g

  • Mass of chlorine, Cl:

\frac{63.32}{100}\times 223.94 = 141.79 g

Now, the number of each element in the unknown compound is determined by the formula:

number of moles = \frac{given mass}{molar mass}

  • Number of moles of C:

number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole

  • Number of moles of H:

number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole

  • Number of moles of Cl

number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole

Dividing each mole with the smallest number of mole, to determine the empirical formula:

C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}

C_{1.5}H_{2.5}Cl_{1}

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is C_{3}H_{5}Cl_{2}.

Empirical mass = 12\times 3+1\times 5+2\times 35.5 = 112 g/mol

In order to determine the molecular formula:

n = \frac{molar mass}{empirical mass}

n = \frac{223.94}{112} = 1.99 \simeq 2

So, the molecular formula is:

2\times C_{3}H_{5}Cl_{2} =  C_{6}H_{10}Cl_{4}

6 0
3 years ago
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