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RoseWind [281]
4 years ago
7

What mass of hcl gas must be added to 1.00 l of a buffer solution that contains [aceticacid]=2.0m and [acetate]=1.0m in order to

produce a solution with ph = 4.11?
Chemistry
1 answer:
Paraphin [41]4 years ago
3 0
PH of acidic buffer = pKa + log [CH₃COONa - HCl] / [CH₃COOH + HCl]
pKa of CH₃COOH = 4.74
Concentration of acetic acid in buffer = 2.0 M
Concentration of sodium acetate = 1.0 M
Concentration of HCl must add = x
pH = 4.74 + log (1-x) / (2+x) = 4.11
x = concentration of HCl must be added = 0.43 M
number of moles of HCl = M * V = 0.43 * 1 = 0.43 mol
mass of HCl must be added = 0.43 * 36.5 = 15.7 g
 
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What Phase is water at 120 degrees Celsius?
Rina8888 [55]
At atmospheric pressure water boils at 100 degC.
So the water would be gas/vapor/steam.
4 0
3 years ago
A chemist must prepare 0.200 L of aqueous silver nitrate working solution. He'll do this by pouring out some aqueous silver nitr
jeyben [28]

A chemist must prepare 0.200 L of 1.00 M aqueous silver nitrate working solution. He'll do this by pouring out 1.82 mol/L aqueous silver nitrate stock solution into a graduated cylinder and diluting it with distilled water. How many mL of the silver nitrate stock solution should the chemist pour out?

Answer: 0.110 L

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,  

M_1 = molarity of stock silver nitrate solution = 1.82 M

V_1 = volume of stock silver nitrate solution = ?  

M_1 = molarity of diluted silver nitrate solution = 1.00 M

V_1 = volume of diluted silver nitrate solution = 0.200 L

Putting in the values we get:

1.82M\times V_1=1.00M\times 0.200L

V_1=0.110L

Therefore, volume of silver nitrate stock solution required is 0.110 L

3 0
3 years ago
If the OH‑ ion concentration in an aqueous solution at 25.0 °C is 6.6 x 10‑4 M, what is the molarity of the H+ ion?
Tresset [83]

Answer:

1.5 × 10⁻¹¹ M

Explanation:

Step 1: Given data

  • Concentration of OH⁻ ([OH⁻]): 6.6 × 10⁻⁴ M
  • Temperature: 25°C
  • Concentration of H⁺ ([H⁺]): ?

Step 2: Consider the self-ionization of water

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

Step 3: Calculate the molar concentration of H⁺

We will use the equilibrium constant for the self-ionization of water (Kw).

Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴ / [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴ / 6.6 × 10⁻⁴

[H⁺] = 1.5 × 10⁻¹¹ M

6 0
4 years ago
A cup holding 125.12g of water has an initial temperature of 26.8 degrees C. After a 35.08g piece of metal, at 99.5 degrees C, i
nignag [31]
<h3>Answer:</h3>

0.620 J/g°C

<h3>Explanation:</h3>

Heat gained or absorbed, Q by a substance is calculated by;

Q = mass × specific heat capacity × Change in temperature

In this case we are given;

  • Mass of water = 125.12 g
  • Initial temperature of water = 26.8 °C
  • Initial temperature of the metal = 99.5°C
  • Final temperature of the mixture = 29.7 °C

We are required to calculate the specific heat capacity of the metal;

<h3>Step 1 : Heat absorbed by water </h3>

Specific heat capacity of water = 4.184 J/g°C

Temperature change of water = 29.7 °C - 26.8°C

                                                   = 2.9 °C

But, Q = m×c×ΔT

Thus, Heat = 125.12 g × 2.9°C × 4.184 J/g°C

                  = 1518.156 Joules

<h3>Step 2; Heat lost by the metal </h3>

Specific heat capacity of the metal = x J/g°C

Temperature change of the metal = 29.7 °C - 99.5°C

                                                         = -69.8 °C

But, Q = mcΔT

Therefore;

Heat lost by the meatl = 35.08 g × x J/g°C × 69.8 °C

                                     = 2.448.584x Joules

<h3>Step 3: C;aculating the specific heat capacity of the metal </h3>

The heat gained by water is equal to the heat lost by the metal

Therefore;

1518.156 Joules = 2.448.584x Joules

x = 1518.156 J ÷ 2.448.584 J

   = 0.620 J/g°C

Therefore, the specific heat of the metal is 0.620 J/g°C

8 0
4 years ago
The heat flux, or the rate of heat transfer per unit area, is measured in watts (Watts) only A. TRUE B. FALSE
Zinaida [17]

Answer: The given statement is false.

Explanation:

Heat flux is defined as the flow of heat or energy per unit time in per unit area. S.I. unit of heat flux is watts per square meter.

Heat flux is represented by the symbol \phi _{q}.

So, it means heat flux is not measured in watts only as it includes per unit area also.

Therefore, we can conclude that the given statement heat flux, or the rate of heat transfer per unit area, is measured in watts (Watts) only, is false.

6 0
3 years ago
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