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Rina8888 [55]
3 years ago
15

An object is thrown downward with an initial velocity of 3 feet per second. The relationship between the distance s it travels a

nd time t is given by s = 3t + 16t2. How long does it take the object to fall 70 feet?
Physics
1 answer:
Vikki [24]3 years ago
3 0

Answer:2 s

Explanation:

Given

initial velocity u=3 ft/s

distance travel s=3t+16t^2

time taken to travel 70 feet

70=3t+16t^2

16t^2+3t-70=0

using x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} to get roots

t=\frac{-3\pm \sqrt{3^2-4(16)(-70)}}{2\cdot 2}

t=2 and -2.19

only feasible time is 2 s

thus it requires 2 s to cover 70 feet

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