We have to find the GCD between 10, 16 and 4 and between x^5, x^4 and x^2
GCD (10,16,4) = 2
GCD (x^5,x^4,x^2) = x^2
So we divide all terms for 2x^2
Final result: 2x^2(5x^3-8x^2+2)
There is no attachment to this questions so we do not know which table represents the following. If you re-question, I would be gladly able to do so.
Yes; you are correct.
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The correct answer is:
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Answer choice: [C]: " x³ − 9x² + 23x <span>− 12 " .
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Note: (a </span>− b) (c − d + e) = ac − ad + ae − bc + bd − be ;
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(x − 4) (x² <span>− 5x + 3) =
x * x</span>² = x³ <span>−
x * 5x = 5x</span>² +
x * 3 = 3x <span>−
4 * x</span>² = 4x² <span>−
-4 * 5x = -20x +
-4 * 3 = -12;
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</span> (x − 4) (x² − 5x + 3) =
x³ − 5x² + 3x −4x² − (-20x) + (-12) ;
= x³ − 5x² + 3x −4x² + 20x − 12 ;
= x³ − 5x² − 4x² + 3x + 20x − 12 ;
= x³ − 9x² + 23x − 12 ; which is:
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Answer choice: [C]: " x³ − 9x² + 23x − 12 " .
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Answer:
24 years
Step-by-step explanation:
let jiri's age be x
Pamela's age=x-15
x+x-15=33
2x-15=33
collect the like terms to similar places
2x=33+15
2x=48
x=24
Once, 14 divided by 16 equals 1 with a remainder of 2
