All categories

2 years ago

Elements in Group 18, at the far right of the periodic table, are called what?

Physics

1 answer:

alekssr [168]2 years ago

5 0

The elements is group 18 on the periodic table are called "Nobel Gases".

You might be interested in

PLEASE HELP

worty [1.4K]

Explanation:

by momentum conservation

64× v=42×3.11

v=2.04m/s

3 0

2 years ago

Read 2 more answers

PLS ANSWER FAST WILL GIVE BRAINLY TIMED TEST

solong [7]

A=F/m
a=(3000000)/(20000)
a=15 m/s^2

4 0

2 years ago

Calculate the speed of a car that travels a distance of 2.4km in 2 minutes

hammer [34]

Answer:

72 kilometres per hour

Explanation:

The formula for calculating speed is distance/time.

So to work this out you would convert 2 minutes into hours. You would divide 2 by 60 to convert it into hours. This is because the standard unit for speed with kilometres is kilometres per hour. Then you would divide 2.4 by that.

1)Divide 2 by 60:

$2/60=0.0333333$

2) Divide 2.4 by 0.0333333.

$2.4/0.0333333=72.00007$

3) Round it.

$72km/h$

3 0

3 years ago

A cathode ray tube is made of glass with a small amount of some kind of gas in it. It has metal electrodes at each end to pick u

LuckyWell [14K]

Scientists could investigate this idea by making cathode ray tubes out of different materials to see if the ray was the same.

6 0

2 years ago

Read 2 more answers

Show that (a)KE=1/2mv2

evablogger [386]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{see \: below}}}}}$

Explanation:

$\underline{ \bold{ \sf{To \: prove \: that \: kinetic \: energy = \frac{1}{2} m {v}^{2} }}}$

Let us consider, a body of mass ' m ' is lying at rest ( initial velocity = 0 ) on a smooth surface. Let a constant force F displaces this body in its own direction by a displacement ' d '. Let 'v' be it's final velocity. The work done ' W ' by the force is given by :

$\sf{W = FD}$

⇒ $\sf{W = m \: \times a \: \times s} \: \: \: \: \: \: \: \: \: ( \: ∴ \: f \: = \: ma \: ; \: s \: = d)$

⇒ $\sf{W = m \: \times \frac{v - u}{t} \times \frac{u + v}{2} \times t \: \: \: \: \: \: \: \: \: (∴ \: a = \frac{v - u}{t} and \: s = \frac{u + v}{2} \times t}$

⇒ $\sf{W = m \times \frac{ {v}^{2} - {u}^{2} }{2} }$

⇒ $\sf{W = \frac{1}{2} m {v}^{2} \: \: \: \: \: \: \: \: \: \: \: \: (since, \: initial \: velocity(u) = 0)}$

The work done becomes the kinetic energy of the body. Thus, the kinetic energy of a body of mass ' m : moving with the velocity equal to 'v ' is 1 / 2 mv²

∴ $\sf{KE= \frac{1}{2} m {v}^{2} }$

$\sf{ \underline{ \bold{ {proved}}}}$

Hope I helped!

Best regards!!

5 0

2 years ago