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morpeh [17]
3 years ago
14

In a Rutherford scattering experiment, each atom in a thin gold foil can be considered a target with a circular cross section. A

lpha particles are fired at this target, with the nucleus as the bull's-eye. The ratio of the cross-sectional area of the gold nucleus to the cross-sectional area of the atom is equal to 2.6 10-7. The radius of the gold atom is 1.4 10-11. What is the radius of the gold nucleus
Physics
1 answer:
Marina CMI [18]3 years ago
7 0

Answer:

Explanation:

the cross-sectional area of the gold nucleus / the cross-sectional area of the atom  = 2.6 x 10⁻⁷

value of radius of gold atom = 1.4 x 10⁻¹¹

cross sectional area = π x (1.4 x 10⁻¹¹ )²

= 6.15 x 10⁻²²  Putting this value in the ratio above

the cross-sectional area of the gold nucleus / 6.15 x 10⁻²² = 2.6 x 10⁻⁷

the cross-sectional area of the gold nucleus = 16 x 10⁻²⁹

radius of nucleus R

π R² = 16 x 10⁻²⁹

R² = 5.1 X 10⁻²⁹

R = 7.14 x 10⁻¹⁵ .

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two cars with initial speed 2v and v, lock their brakes and skid to a stop. what is the ratio of the distance travelled
denpristay [2]

Answer:

4:1

Explanation:

Given that the initial speed of the first car, u = 2v while the initial speed of the second car, u = v. To find the distance travelled, we are going to apply one of the equations of motion. The equation chosen is

v² = u² - 2as, where

s = the distance needed

a = acceleration due to gravity

u = initial velocity which is v & 2v

v = final velocity which is 0

For the first car with initial velocity, 2v, on substituting into the equation, we have

v² = u² - 2as(1)

0 = 4v - 2as(1)

4v = 2as(1)

2v = as(1), making s(1) subject of formula we have

s(1) = 2v/a

Taking the second car, we have u = v

v² = u² - 2as(2)

0 = v - 2as(2)

v = 2as(2), making s(2) subject of formula, we have

s(2) = v/2a

Not, ratio of s1 : s2 =

2v/a : v/2a

s1/s2 = 2v/a ÷ v/2a

s1/s2 = 2v/a * 2a/v

s1/s2 = 4av/av

s1/s2 = 4/1

Therefore, the ratio of the first car to the second car is 4:1

Please leave a like if it helped you

8 0
3 years ago
A professional cyclist rides a bicycle that is 92 percent efficient. For every 100 joules of energy he exerts as input work on t
dolphi86 [110]
The bicycle is 92% efficient, meaning 92% of energy input is converted to useful (in this case kinetic) energy. Just find 92% (=0.92) of the given input. So:
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The highest waterfall in the world is the Salto Angel in Venezuela. Its longest single falls has a height of 807 m. If water at
valentina_108 [34]

Answer:

Temperature at the bottom will be 19.18°C

Explanation:

We have given height h = 807 m

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So mc\Delta T=mgh

\Delta T=\frac{gh}{c}=\frac{9.8\times 807}{4200}=1.88^{\circ}C

So temperature at the bottom = 17.3+1.88 = 19.18°C

   

5 0
3 years ago
True or False. Electromagnetic waves travel fastest through a vacuum.
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A student rides her bike to school. Her school is 5 miles from home. She travels at an average rate of 15 miles per hour. How mu
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