Answer:
Explanation:
Given that,
Initial angular velocity,
Acceleration of the wheel,
Rotation,
Let t is the time. Using second equation of kinematics can be calculated using time.
Let is the final angular velocity and a is the radial component of acceleration.
Radial component of acceleration,
So, the required acceleration on the edge of the wheel is .
Answer:
The self-induced emf in this inductor is 4.68 mV.
Explanation:
The emf in the inductor is given by:
Where:
dI/dt: is the decreasing current's rate change = -18.0 mA/s (the minus sign is because the current is decreasing)
L: is the inductance = 0.260 H
So, the emf is:
Therefore, the self-induced emf in this inductor is 4.68 mV.
I hope it helps you!
So the initial velocity is 15 m/s, the final velocity is 0 since it's at a complete stop and time is 10 seconds. Therefore:
Therefore, the acceleration is -1.5 m/s^2. The reason it's negative is due to the fact that the vector is going against it's original movement since it's decelerating.