Answer:
0.73 W/m²
0.2522 W/m²
Explanation:
= Unpolarized light = 1.46 W/m²
= Analyzer angle = 54°
Light through first filter

The intensity of the light leaving the polarizer is 0.73 W/m²
After passing through analyzer

The intensity of the light that reaches the photocell is 0.2522 W/m²
The refractive index is essentially the speed of light through a vacuum (extremely similar to air) divided by the speed of light through given medium.
I also attached some of my physics notes on refraction and that sort of jazz as they may help :)
Answer:
1.
-Deflection force
2.q-Charge
3.v-Velocity of the charge
4.B-Perpendicular magnetic field strength
Explanation:
We are given that magnetic deflection

We have to match each symbol in formula with what it represents.
In this formula
Deflection force
q=Charge of particle
v=Velocity of charge
B=Perpendicular magnetic field strength
Therefore,
1.
-Deflection force
2.q-Charge
3.v-Velocity of the charge
4.B-Perpendicular magnetic field strength
The direction the telescope may be heading ummm honestly I don’t know the answer to that
Answer:
12
N
in the direction opposite to electric field.
Explanation:
Force on a charged particle
q
due to electric field
E
is given by
→
F
=
q
→
E
|
F
|
=
−
0.06
C
×
200
N
C
=
−
12 N
Here negative indicates that force is in the direction opposite to electric field.