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stiks02 [169]
3 years ago
13

Which one of the following is most likely to lose electrons when forming an ion?

Chemistry
1 answer:
otez555 [7]3 years ago
7 0

Answer:

Option A) Na

Explanation:

From the options given above, sodium (Na) is most likely to lose electron to form ion

Na is a group 1 metal. Metals form ions by losing electron(s).

From the options given above, only Na is a metal and so it is most likely to form ion by losing electron

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1 - 2Na + O2 ➔ Na2O Balanced Not Balanced
Mrrafil [7]

Answer:

1 not

2 not

3 not

4 balanced

5 not

6 not

7 balanced

Explanation:

the amount of elements must be equal in the reactant and products

5 0
3 years ago
Uranium, an important component of both nuclear weapons and nuclearreactors, has two major isotopes, U-238, which has a half-lif
elixir [45]

Answer:

Hello your question is poorly written below is the well written question

Uranium, an important component of both nuclear weapons and nuclear reactors, has two major isotopes, U-238, which has a half-life of  approximately 4.5 billion years, and U-235, which has a half-life of approximately 700 million years. Both were present in equal amounts at the time of the creation of the Earth, 4.5  billion years ago. How many years after the creation of the Earth had the amount of radiation from uranium decayed to half the amount present at the time of the creation of the Earth

Answer : 140 billion years

Explanation:

Given that :

U-238   h1/2 = 4.5 billion years

U-235   h1/2 = 700 million years

At the beginning both Isotopes where present in equal amount

Determine the T years before the amount of Uranium decays to Half

T =   ?    N'2 = N1 / 2

we know that N = No ( 1/2 )^h   where h = time / half-life time

attached below is the detailed solution of the given problem

6 0
3 years ago
A common laboratory method for preparing a precipitate is to mix solutions containing the component ions. Does a precipitate for
laiz [17]

Answer:

CaF2 will not precipitate

Explanation:

Given

Volume of Ca(NO3)2 = 10 ml

Molar concentration of Ca(NO3)2 = 0.001

Volume of NaF = 10 ml

Molar concentration of  NaF  = 0.0001

Ksp for CaF2 = 3.2 * 10^ {-11}

CaF2 will precipitate if Q for the reaction is greater than ksp of CAF2

Moles of calcium ion

= 10 * 0.001\\= 0.01

[Ca2+] = \frac{0.01}{10 + 10} \\= \frac{0.01}{20} \\= 5 * 10^{-4}

Moles of F- ion

= 10 * 0.0001\\= 0.001

[F-] = \frac{0.001}{10 + 10} \\= \frac{0.001}{20} \\= 5 * 10^{-5}

Q = [Ca2+] [F-]^2\\= (5 * 10^{-4}) * (0.5* 10^-4)\\= 1.25 * 10^{-12}

Q is lesser than Ksp value of CaF2. Hence it will not precipitate

5 0
3 years ago
How many molecules are in 2.570 moles of H2
docker41 [41]
A lot of molecules will be in 2.570 moles of H2
5 0
3 years ago
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A reaction contains two reactants, A and B. If A is doubled, there will be a greater number of effective collisions between reac
svlad2 [7]
True true true true true
4 0
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