What is the mass in grams of 13.2 amu?

A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If

NemiM [27]

Answer:

<h3>25.0 grams is the mass of the steel bar.</h3>

Explanation:

Heat gained by steel bar will be equal to heat lost by the water

$Q_1=-Q_2$

Mass of steel= $m_1$

Specific heat capacity of steel = $c_1=0.452 J/g^oC$

Initial temperature of the steel = $T_1=2.00^oC$

Final temperature of the steel = $T_2=T=21.50^oC$

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2= 105 g$

Specific heat capacity of water= $c_2=4.18 J/g^oC$

Initial temperature of the water = $T_3=22.00^oC$

Final temperature of water = $T_2=T=21.50^oC$

$Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))$

On substituting all values:

$(m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}$

<h3>25.0 grams is the mass of the steel bar.</h3>

3 0

2 years ago

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Which kind of energy does matter have when it is in motion?

Rzqust [24]

Answer:

Kinetic Energy

Explanation:

Kinetic energy is the energy inside moving objects of things.

8 0

2 years ago

Read 2 more answers

(2pts) During the Purification of Lactate Dehydrogenase (LDH) experiment, you will need 50ml of buffer A150. Buffer A150 is 30mM

torisob [31]

Answer:

The answer is " $20 \ mL$ "

Explanation:

Given:

Molarity= number of moles

because it is 1 Liter

$\to \frac{0.03\ moles}{1.5 moles}=0.02\ L= 20 \ mL \ of\ Tris\\\\$

therefore,

it takes 20 mL of Tris.

$\to \frac{0.150 \ moles}{5\ moles} =0.03\ L\\\\$

$= 30 \ mL \ of\ Nacl$

So, take $20 \ mL\ of\ NaCl.$

6 0

2 years ago

Copper(II) sulfide is oxidized b molecular oxygen to produce gaseous sulfur trioxide and solid copper (II) oxide. The gaseous pr

Tasya [4]

Explanation:

Copper(II) sulfide reacts with oxygen gas to give solid copper(II) oxide and sulfur trioxide gas.

The reaction is given as:

$CuS+2O_2\rightarrow CuO(s)+SO_3(g)$

When 1 mol copper(II) sulfide react with 2 moles of oxygen gas it gives 1 mol of solid copper(II) oxide and 1 mol of sulfur trioxide gas

The gas formed in above reaction that is sulfur trioxide reacts with water to give sulfuric acid or hydrogen sulfate.

The reaction is given as:

$SO_3(g)+H_2O(l)\rightarrow H_2SO_4(aq)$

1 mol of sulfur trioxide gas reacts with 1 mol of liquid water to produce 1 molo of liquid hydrogen sulfate or sulfuric acid

3 0

2 years ago

how many grams of oxygen gas are needed to produce 10.0 grams of carbon dioxide according to the balanced equation of CH4

Alinara [238K]

Molar mass of :

O2 = 16 * 2 = 32 g/mol

CO2 = 12 + 16 * 2 = 44 g/mol

<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
↓ ↓
2 moles 1 mole

2* 32 g O2 ----------> 1* 44 g CO2
x g O2 ------------> 10.0 g CO2

44 x = 2 * 32*10.0

44 x = 640

$x = \frac{640}{44}$

$x = 14.54 g$ of O2

7 0

2 years ago