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xxTIMURxx [149]
3 years ago
12

PLEASE HELP A car accelerates from rest at 2.92 m/s2 What is the velocity at the end of 5.1 s? Answer in units of m/s. What is t

he displacement after 5.1 s? Answer in units of m.
Physics
1 answer:
uranmaximum [27]3 years ago
6 0

Answer:

first you have to organize the data. a=acceleration t=time v0=inicial velocity vf=final velocity

a=2.92m/s2

t=5.1s

vf=?

v0=0

now the formula you have to use is: vf=vi+a*t (final velocity equals to inicial velocity plus acceleration times time)

Explanation:

i was the best at my class, hope it helped

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Answer:

The velocity of the cart at the bottom of the ramp is 1.81m/s, and the acceleration would be 3.30m/s^2.

Explanation:

Assuming the initial velocity to be zero, we can obtain the velocity at the bottom of the ramp using the kinematics equations:

v=v_0+at\\\\v^2=v_0^2+2ad

Dividing the second equation by the first one, we obtain:

v=\frac{v_0^2+2ad}{v_0+at}

And, since v_0=0, then:

v=\frac{2ad}{at}\\\\v=\frac{2d}{t}\\\\v=\frac{2(0.50m)}{0.55s}\\\\v=1.81m/s

It means that the velocity at the bottom of the ramp is 1.81m/s.

We could use this data, plus any of the two initial equations, to determine the acceleration:

v=v_0+at\\\\\implies a=\frac{v}{t}\\\\a=\frac{1.81m/s}{0.55s}\\\\a=3.30m/s^2

So the acceleration is 3.30m/s^2.

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3 years ago
What drives plate tectonics in the earths interior
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balls a, with a mass of 20 kg, is moving to the right at 20 m/s. At what velocity should Ball B, with a mass of 40 kg, move so t
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