Answer:
Explanation:
q = - 15 n C = - 15 x 10^-9 c
(a) d = 0.9 cm = 0.009 m
electric field on proton, E = Kq/d²
E = 9 x 10^9 x 15 x 10^-9 / (0.009)²
E = 1.67 x 10^6 N/C
Force on proton, F = charge on proton x Electric field
F = 1.6 x 10^-19 x 1.67 x 10^6 = 2.67 x 10^-13 N
acceleration of proton, a = F / m
a = (2.67 x 10^-13) / (1.67 x 10^-27)
a = 1.6 x 10^14 m/s²
(B) the direction of acceleration is towards the bead, as the force is attractive.
(C) d = 0.9 cm = 0.009 m
electric field on proton, E = Kq/d²
E = 9 x 10^9 x 15 x 10^-9 / (0.009)²
E = 1.67 x 10^6 N/C
Force on electron, F = charge on electron x Electric field
F = 1.6 x 10^-19 x 1.67 x 10^6 = 2.67 x 10^-13 N
acceleration of proton, a = F / m
a = (2.67 x 10^-13) / (9.1 x 10^-31)
a = 3 x 10^17 m/s²
(D) the direction of acceleration is away from the bead, as the force is repulsive.
