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Arturiano [62]
3 years ago
11

A classic demonstration illustrating eddy currents is performed by dropping a permanent magnet inside a conducting cylinder. The

magnet does not go into free fall. Instead it reaches terminal velocity and can take a few seconds to drop a length of about a meter. Suppose the mass of the magnet is 70 g and width of 1.0 cm. It falls with a terminal velocity of 10 cm/s and the length of the pipe is 80 cm. The magnitude of the Joule heating from the eddy currents is approximately:________
Physics
1 answer:
kvv77 [185]3 years ago
4 0

Answer:

The correct solution is "0.69 N".

Explanation:

The given values are:

Mass of magnet,

m = 70 g

or,

   = 0.07 kg

Width,

= 1.0 cm

Velocity,

= 10 cm/s

Length of the pipe,

= 80 cm

Whenever the velocity is constant, then the net force which is acting on the magnet will be "0".

On the magnet,

The up-ward force will be:

⇒  F=mg

On substituting the values, we get

⇒      =0.07\times 9.8

⇒      =0.69 \ N

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At rest, hydrogen has a spectral line at 116 nm. if this line is observed at 107 nm for the star sirius, how fast is sirius movi
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2.3275862×10¹²km/s fast is sirius moving in km/s.

<h3>Briefing:</h3>

Hydrogen has a spectral line at = 116nm=116×10⁻⁹m

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Now, from the Hubble's law

V=(\Delta \lambda / \lambda)×C

Where,

v is the velocity

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on substituting the respective values, we get

V=(9/116)×3×10⁸=23275862.069×10⁵m/s

V=2.3275862×10¹²km/s.

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Two different sources of radiation give the same dose equivalent in Sv. Does this mean that the radiation from each source has t
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Calculate the kinetic energy, in joules of a 1160-kg automobile moving at 19.0 m/s.
Rudiy27

Answer:

Explanation:

K.E=1/2 mv²

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so k.e=1/2*1160*(19.0)²

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