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Sidana [21]
3 years ago
13

G summarize what you know about how changes in frequency and amplitude determine the characteristics

Physics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

Loudness and pitch are the characteristics of a sound related to amplitude and frequency.

Explanation:

Loudness and pitch are the characteristics of a sound that are related with the frequency and amplitude of a sound. If any change occurs in the frequency and amplitude of a sound, change also occurs in the loudness and pitch of a sound. If a source has larger amplitude so it produces large loudness or volume of a sound. On the other hand when the frequency is higher than the pitch will also be higher and the sound produce will be high.

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The radius of a sphere is increasing at a rate of 4 mm/s. How fast is the volume increasing when the diameter is 60 mm?
jok3333 [9.3K]
V = [4/3]π r^3 => [dV / dr ] = 4π r^2

[dV/dt] = [dV/dr] * [dr/dt]

[dV/dt] = [4π r^2] * [ dr/ dt]

r = 60 mm, [dr / dt] = 4 mm/s

[dV / dt ] = [4π(60mm)^2] * 4mm/s = 180,955.7 mm/s 


5 0
3 years ago
You hear that a storm is moving 15km/HR north. You have been given the storm's______
Elodia [21]
You have been given the storm's velocity.
7 0
3 years ago
Which of the following would create voltage in a coil of wire?
zubka84 [21]
Its d all the above your welcome
8 0
3 years ago
Equations E = 1 2πε0 qd z3 and E = 1 2πε0 P z3 are approximations of the magnitude of the electric field of an electric dipole,
tamaranim1 [39]

Answer:

The ratio of E_{app} and E_{act} is 0.9754

Explanation:

Given that,

Distance z = 4.50 d

First equation is

E_{act}=\dfrac{qd}{2\pi\epsilon_{0}\times z^3}

E_{act}=\dfrac{Pz}{2\pi\epsilon_{0}\times (z^2-\dfrac{d^2}{4})^2}

Second equation is

E_{app}=\dfrac{P}{2\pi\epsilon_{0}\times z^3}

We need to calculate the ratio of E_{act} and E_{app}

Using formula

\dfrac{E_{app}}{E_{act}}=\dfrac{\dfrac{P}{2\pi\epsilon_{0}\times z^3}}{\dfrac{Pz}{2\pi\epsilon_{0}\times (z^2-\dfrac{d^2}{4})^2}}

\dfrac{E_{app}}{E_{act}}=\dfrac{(z^2-\dfrac{d^2}{4})^2}{z^3(z)}

Put the value into the formula

\dfrac{E_{app}}{E_{act}}=\dfrac{((4.50d)^2-\dfrac{d^2}{4})^2}{(4.50d)^3\times4.50d}

\dfrac{E_{app}}{E_{act}}=0.9754

Hence, The ratio of E_{app} and E_{act} is 0.9754

8 0
3 years ago
If 4 x 10^21 electrons pass through a wire connected to a 15 ohm resistor in 3 s, how much electric
sammy [17]

Answer:

1.) Current = 213.33A

2.) Potential difference = 3200 V

Explanation:

Given that

Number of electrons n = 4 x 10^21 electrons

Resistance R = 15 ohm

Time t = 3 s

From the definition of current ;

Current is the rate of flow of changes. That is,

Current I = Q/t

Where

Q = 4 × 10^21 × 1.6 × 10^-19

Q = 460C

Current I = 460/3

Current I = 213.33 A

Using Ohms law which state that

V = IR

Substitute the resistance R and current I into the formula above

Potential difference V = 213.3 × 15

Potential difference V = 3200 V

6 0
3 years ago
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