To solve this problem we must apply the concepts related to Tangential Acceleration based on angular velocity and acceleration, and therefore, we must also calculate angular velocity based on the given frequency. For all these problems we will take the Units to the International System. The maximum acceleration would then be defined as,

Here,
= Angular velocity
A = Amplitude
At the same time the angular velocity is described as,

Here f means the frequency of the wave. Substituting,




Replacing at the first equation,


Therefore the maximum particle acceleration for a point on the string is 
Answer:
The wood block reaches a height of 4.249 meters above its starting point.
Explanation:
The block represents a non-conservative system, since friction between wood block and the ramp is dissipating energy. The final height that block can reach is determined by Principle of Energy Conservation and Work-Energy Theorem. Let suppose that initial height has a value of zero and please notice that maximum height reached by the block is when its speed is zero.



(1)
Where:
- Maximum height of the wood block, in meters.
- Initial speed of the block, in meters per second.
- Kinetic coefficient of friction, no unit.
- Gravitational acceleration, in meters per square second.
- Mass, in kilograms.
- Distance travelled by the wood block along the wooden ramp, in meters.
- Inclination of the wooden ramp, in sexagesimal degrees.
If we know that
,
and
, then the height reached by the block above its starting point is:


The wood block reaches a height of 4.249 meters above its starting point.
Answer:
90 degree
Explanation:
Electric field line is vertical to the electric field line.
Answer:
Definimos:
Rapidez media es igual al cociente entre la distancia recorrida y el tiempo que se tarda en recorrer esa distancia.
En este caso la distancia recorrida es 400m, y el tiempo que se tarda es 30s, entonces la rapidez media va a ser:
RM = 400m/30s = 13.33 m/s
La velocidad media por otro lado, es igual al cociente entre el desplazamiento y el tiempo necesario para desplazarse.
El desplazamiento es igual a la distancia entre la posición final y la posición inicial, que en este caso eso 40m, y el tiempo necesario sigue siendo 30s, entonces la velocidad media va a ser:
VM = 40m/30s = 1.33 m/s