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Assoli18 [71]
3 years ago
15

5. A sunbather at the beach absorbs the thermal energy from the sun through

Physics
1 answer:
Brums [2.3K]3 years ago
8 0
Answer: B, Radiation

Explanation: idk just got that out from Mr.Google
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Consider a sample of gas in a container on a comfortable spring day in chicago, il. the celsius temperature suddenly doubles, an
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To solve this problem, we must first assume that the gas acts like an ideal gas so that we can use the ideal gas equation:

 P V = n R T

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant and T is the absolute temperature

 

Assuming that the number of moles is constant, then we can write all the variables in the left side:

P V / T = k            where k is a constant (n times R)

 

Equating two conditions or two states:

P1 V1 / T1 = P2 V2 / T2

We are given that V2 = 2 V1 therefore

P1 V1 T2 = P2 (2V1) T1

P1 T2 = 2 P2 T1

 

Additionally we are given that the temperature in Celsius is doubled, however in the formula we use the absolute temperature in Kelvin, therefore:

T1 (K) = T1 + 273.15

T2 (K) = 2T1 + 273.15

and P1 = 12 atm

 

Substituting:

<span>12 (2T1 + 273.15)  = 2 P2 (T1 + 273.15)</span>

P2 = 6 (2T1 + 273.15) / (T1 + 273.15)

 

Assuming that a nice spring day in Chicago has a temperature of 15 Celsius, therefore:

P2 = 6 (2*15 + 273.15) / (15 + 273.15)

<span>P2 = 6.312 atm</span>

3 0
3 years ago
Which statement best describes electrons?
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They are positive and remain inside the nucleus.
4 0
2 years ago
A tank contains gas at 13.0°C pressurized to 10.0 atm. The temperature of the gas is increased to 95.0°C, and half the gas is re
fomenos

Answer:

The pressure of the remaining gas in the tank is 6.4 atm.

Explanation:

Given that,

Temperature T = 13+273=286 K

Pressure = 10.0 atm

We need to calculate the pressure of the remaining gas

Using equation of ideal gas

PV=nRT

For a gas

P_{1}V_{1}=nRT_{1}

Where, P = pressure

V = volume

T = temperature

Put the value in the equation

10\times V=nR\times286....(I)

When the temperature of the gas is increased

Then,

P_{2}V_{2}=\dfrac{n}{2}RT_{2}....(II)

Divided equation (I) by equation (II)

\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}

\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}

P_{2}=\dfrac{10\times368}{2\times286}

P_{2}= 6.433\ atm

P_{2}=6.4\ atm

Hence, The pressure of the remaining gas in the tank is 6.4 atm.

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2 years ago
Which properties of plastics allow them to be solutions to many complex problems in the world? Check all that apply. A.chemicall
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the answers are A, B, C, E  HOPED THIS HELPED

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Objects have a tendency to resist changing their motion. This property is called: *
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Answer:

The answer your looking for is option 2 - Inertia

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