Supposing complete ionization:
<span>BaBr2 → Ba{2+} + 2 Br{-} </span>
<span>(2.23 × 10^–4 g BaBr2) / (297.135 g BaBr2/mol) / (2.00 L) = 3.75 × 10^-7 mol/L BaBr2 </span>
<span>(3.75 × 10^-7 mol/L BaBr2) x (1 mol Ba{2+} / 1 mol BaBr2) = 3.75 × 10^-7 mol/L Ba{2+} </span>
<span>(3.75 × 10^-7 mol/L BaBr2) x (2 mol Br(-} / 1 mol BaBr2) = 7.50 × 10^-7 mol/L Br{-}</span>
Answer:
heating point for water - 100°
The answer is B "the reaction is exothermic", and C "the reactants lost internal energy."
The engine ran for 10 second
