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2 years ago

Plsss helppp dont guess

Chemistry

2 answers:

Doss [256]2 years ago

8 0

Answer:

B is the correct answer..........

kari74 [83]2 years ago

6 0

maybe 1+8 (4+548) 4/6 4+4

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The student is now told that the four solids, in no particular order, are calcium bromide (CaBr2), sugar (C6H12O6), butanoic aci

sladkih [1.3K]

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How did the First Great Awakening affect attitudes toward religion in the colonies during the early 1700s?

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3 years ago

What is the value of for this aqueous reaction at 298 K? A+B↽⇀C+D ΔG°=12.86 kJ/mol K=

agasfer [191]

Answer:

The equilbrium constant is 179.6

Explanation:

To solve this question we can use the equation:

ΔG = -RTlnK

Where ΔG is Gibbs free energy = 12.86kJ/mol

R is gas constant = 8.314x10⁻³kJ/molK

T is absolute temperature = 298K

And K is equilibrium constant.

Replacing:

12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK

5.19 = lnK

e^5.19 = K

179.6 = K

<h3>The equilbrium constant is 179.6</h3>

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2 years ago

Write the structural formula for m-chlorophenyl ethyl ether.

Sliva [168]

Answer: C(OCH2CH3)CHCClCH(CH)2

Explanation:

The structural formula for m-chlorophenyl ethyl ether is

C(OCH2CH3)CHCClCH(CH)2.

The structural formula shows the step-by-step linkages.

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3 years ago

What’s a predator? Are predators animals?

Setler [38]

Answer:

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Explanation:

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2 years ago

Read 2 more answers

The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihyd

kenny6666 [7]

Answer:

The answer is " $= 0.078 \ kg \ H_2$ ".

Explanation:

calculating the moles in $CH_4 =\frac{PV}{RT}$

$=\frac{(0.58 \ atm) \times (923 \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(232^{\circ} C +273)}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(505)K}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (41.4605 \frac{L \cdot atm}{mol})}\\\\= 12.9 \ mol$

Eqution:

$CH_4 +H_2O \to 3H_2+ CO \ (g)$

Calculating the amount of $H_2$ produced:

$= 12.9 \ mol CH_4 \times \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2$

So, the amount of dihydrogen produced = $0.078 \frac{kg}{s}$

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2 years ago