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3 years ago

How many moles of Cl2 will produce 0.35 miles of NaCl when reacted with excess Na?

1 answer:

6 0

This question is based in mole ratios. for every mole of cl2, 2 moles of NaCl will be produced. so half of the moles of NaCl gives the moles of Cl2 required. therefore divide 0.35 by 2

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A student is given a 2.002 g sample of unknown acid and is told that it might be butanoic acid, a monoprotic acid (HC4H7O2, equa

Elina [12.6K]

Answer: The identity of the unknown acid is butanoic acid or ascorbic acid.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Molarity of NaOH solution = 0.570 M

Volume of solution = 39.55 mL

Putting values in above equation, we get:

$0.570M=\frac{\text{Moles of NaOH}\times 1000}{39.55}\\\\\text{Moles of NaOH}=\frac{0.570\times 39.55}{1000}=0.0225mol$

The chemical equation for the reaction of NaOH and monoprotic acid follows:

$NaOH+HX\rightarrow NaX+H_2O$

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of HX

So, moles of monoprotic acid = 0.0225 moles

The chemical equation for the reaction of NaOH and diprotic acid follows:

$2NaOH+H_2X\rightarrow 2NaX+2H_2O$

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of diprotic acid

So, moles of diprotic acid = $\frac{0.0225}{2}=0.01125moles$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

For butanoic acid:

Mass of butanoic acid = 2.002 g

Molar mass of butanoic acid = 88 g/mol

Putting values in above equation, we get:

$\text{Moles of butanoic acid}=\frac{2.002g}{88g/mol}=0.02275mol$

For L-tartaric acid:

Mass of L-tartaric acid = 2.002 g

Molar mass of L-tartaric acid = 150 g/mol

Putting values in above equation, we get:

$\text{Moles of L-tartaric acid}=\frac{2.002g}{150g/mol}=0.0133mol$

For ascorbic acid:

Mass of ascorbic acid = 2.002 g

Molar mass of ascorbic acid = 176 g/mol

Putting values in above equation, we get:

$\text{Moles of ascorbic acid}=\frac{2.002g}{176g/mol}=0.01137mol$

As, the number of moles of butanoic acid and ascorbic acid is equal to the number of moles of acid getting neutralized.

Hence, the identity of the unknown acid is butanoic acid or ascorbic acid.

5 0

3 years ago

Please help it’s due today I will give brainliest

Thepotemich [5.8K]

1st and 4th options are suitable answers, as these 2 changes are not exactly physical changes as it cant return back to original form and as well as its not cooling, so I feel its 1st and 4th options

7 0

3 years ago

Question 6: Iron metal and chlorine gas react to form iron (III) chloride: 2 Fe(s) + 3 Cl2 (g) → 2 FeCl3 (s)

Bas_tet [7]

10 gm of Fe will consumes 19 gm Cl₂ and will produces 29 gm FeCl₃.

What ois Theoretical yield ?

The quantity of a product obtained from a reaction is expressed in terms of the yield of the reaction.

The amount of product predicted by stoichiometry is called the theoretical yield, whereas the amount obtained actually is called the actual yield.

As 2 moles (111.68 g) of Fe consumes 213 gm of Cl₂ to produce 2FeCl₃

Therefore ,

10 gm of Fe will consumes = 213 / 111.68 x 10 = 19 gm Cl₂

As 2 moles (111.68 g) of Fe produces 2 mole (324 gm) of FeCl₃

Therefore ,

10 gm of Fe will produces = 324 / 111.68 x 10 = 29 gm FeCl₃

Hence , 10 gm of Fe will consumes 19 gm Cl₂ and will produces 29 gm FeCl₃.

Learn more about Theoretical yield here ;

brainly.com/question/12704041

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4 0

2 years ago

Consider the titration of 30.0 mL of 0.200 M HClO4 with 0.100 M KOH. Calculate the pH of the resulting solution after the follow

Umnica [9.8K]

Answer:

xxfbhg CV ccdfg CD did ffg bgg exvgex

8 0

3 years ago

**25 POINTS**. I doubt anyone will do this but it's worth a try to ask. To do this exercise, you will need fifteen containers, f

Travka [436]

Answer:

done not that hard

Explanation:

6 0

3 years ago