Answer:
CH
Explanation:
We have to obtain the mass of carbon and hydrogen in CO2 and H2O respectively.
For carbon in CO2;
0.845 * 12/44 = 0.23 g
For hydrogen in H20;
0.173 * 2/18 = 0.019 g
We convert the masses to moles of carbon and hydrogen
For carbon - 0.23/ 12 = 0.019 moles
For hydrogen - 0.019/1 = 0.019 moles
Dividing by 0.019 moles for carbon and hydrogen we have the emperical formula of the compound as CH
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1) Reaction: 3Mg + N₂ → Mg₃N₂.
m(Mg) = 0,225 g
n(Mg) = 0,225 g ÷ 24,3 g/mol = 0,009 mol.
n(Mg) : n(N₂) = 3 : 1
n₁(N₂) = 0,003 mol.
n₂(N₂) = 0,5331 ÷ 28 = 0,019 mol.
n₃(N₂) = 0,019 mol - 0,003 mol = 0,016, m(N₂) = 0,016mol·28g/mol=0,4467g.
or simpler: m(N₂) = 0,225 g + 0,5331 - 0,3114 g = 0,4467 g.
2) Answer is: 6 <span>of fluorine atoms are combined with one uranium atom.
</span>m(U) = 209 g.
m(F) = 100 g.
n(U) = m(U) ÷ M(U)
n(U) = 209 g ÷ 238 g/mol.
n(U) = 0,878 mol.
n(F) = m(F) ÷ M(F)
n(F) = 5,263 mol
n(U) : n(F) = 0,878 mol : 5,263 mol /:0,878.
n(U) : n(F) = 1 : 6.
n - amount of substance
Answer: -
Fission creates large amounts of radioactive waste.
Explanation: -
During nuclear fission, by products are formed. These by products are radioactive in nature. They give radiation. These radiation causes a lot of harm to humans including cancer and mutations.
Thus, Fission creates large amounts of radioactive waste.
1mol N2 + 3mol H2 → 2mol NH3
<span>Because you are dealing with gases, at the same temperature and pressure you can say: </span>
<span>1volume N2 + 3 volumes H2 → 2 volumes NH3 </span>
<span>OR: 4 volumes reactants = 2 volumes products. </span>
<span>You have 1.9+5.7 = 7.6 volumes reactants, which must give 7.6/2 = 3.8 volumes of NH3 </span>
<span>Answer: 3.8 litres of NH3 will be formed</span>
