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Advocard [28]
4 years ago
9

50 J of work was performed in 20 seconds. How much power was used to do this task?

Physics
2 answers:
dezoksy [38]4 years ago
8 0
I would go with 2.5 because all you do is divide 50 and 20 

That would give you 2.5 :) 
nordsb [41]4 years ago
5 0
Power is the measurement of work.. you can find power by dividing work by time, so you have P=50J/20s leading to 2.5 J of power being used.
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Marrrta [24]
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8 0
3 years ago
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jeka57 [31]

Answer:

W = 0J

Explanation:

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W = f d (cos θ)

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3 0
3 years ago
Can anyone help me with questions a and c​
Ganezh [65]

Answer:

a)

n=sin i/sin r

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b)

sin c=1/n

sin c=1/0.713

sin c= 1.403

c=sin⁻¹(1.403)

c= 40.842°

Explanation:

i hope it will be helpful

plzzz mark as brainliest

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liberstina [14]
B: 0.4 kilometers ...
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