Answer:
C
Explanation:
sorry if its wrong but i think its right
For a hydrocarbon, the combustion reactions are the following:
C + O₂ --> CO₂
H₂ + 1/2 O₂ --> H₂O
The molar mass of CO₂ is 44 g/mol while C is 12 g/mol. Let's solve for amount of C in hydrocarbon.
Mass of C = (14.1 g CO₂)(1mol/44g)(1 mol C/1 mol CO₂)(12 g/mol) = 3.845 g C
So, that means that the mass of hydrogen is:
Mass of H = 4.4 - 3.845 = 0.555 g
Moles C = 3.845/12 = 0.32042
Moles H = 0.555/1 = 0.555
Divide both by the smaller value, 0.32042.
C: 0.32042/0.32042 = 1
H: 0.555/0.32042 = 1.732
We have to get an answer that is closest to a whole number. Let's try multiplying both with 4.
C: 1*4 = 4
H: 1.732*4 = 6.93≈7
<em>Thus, the empirical formula is C₄H₇.</em>
Answer:
The light wave could be absorbed by the object, in which case its energy is converted to heat.
Explanation:
Answer : The concentration of NO is, 
Solution : Given,
Concentration of
and
= 152 M
Equilibrium constant,
= 
The given equilibrium reaction is,

The expression of
will be,
![K_c=\frac{[NO]^2}{[N_2][O_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%7D)
Now put all the given values in this expression, we get:
![2.0\times 10^{-9}=\frac{[NO]^2}{152\times 152}](https://tex.z-dn.net/?f=2.0%5Ctimes%2010%5E%7B-9%7D%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B152%5Ctimes%20152%7D)
![[NO]=6.8\times 10^{-3}M](https://tex.z-dn.net/?f=%5BNO%5D%3D6.8%5Ctimes%2010%5E%7B-3%7DM)
Therefore, the concentration of NO is, 
The maximum amount of XeF4 that could be produced is 0.5 moles.
XeF4 = Xe (g) 2 F2 (g) (g)
Xe and F2 have a mole ratio of 1:2. Because of this, the reaction would be limited by F2 when there is 1 mole of Xe and 1 mole of F2.
<h3>What is mole ratio?</h3>
The mole ratio is the ratio of any two compounds' mole amounts that are present in a balanced chemical reaction.
A comparison of the ratios of the molecules required to accomplish the reaction is given by the balancing chemical equation.
A mole ratio is a conversion factor used in chemical reactions to link the mole quantities of any two compounds. A conversion factor's numbers are derived from the balanced chemical equation's coefficients.
To learn more about mole ratio from the given link:
brainly.com/question/14425689
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