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Scilla [17]
3 years ago
6

A ray of yellow light has a wavelength of about 5.8×10−7 m. Will exposure to yellow light cause electrons to be emitted from ces

ium?
Chemistry
1 answer:
Dima020 [189]3 years ago
8 0
Given the wavelength of the yellow light (700 nm. in this case) we can find the frequency 
<span>by dividing the speed of light c by the wavelength w, that is: f = c/w and we know that </span>
<span>c is equal to 2.998 * 10**8 meters per second. </span>
<span>So the frequency f = (2.998 * 10**8) / (7.0 * 10**-7) = 4.283 * 10**14 cycles per sec. </span>
<span>(or Hz.) Since the threshold frequency of Cs is 9.39 * 10**14 Hz, the red light doesn't </span>
<span>have a high enough frequency (or energy) to cause electron emission. </span>
<span>Hope this answers your question.</span>
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The Principle Quantum Number describes what aspect of electron orbitals?
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3 years ago
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7 0
3 years ago
Read 2 more answers
H-1
bonufazy [111]
Answer = B = Neutrons and Mass Number

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Atomic number is the number of protons present in an atom.

So, in isotopes the number of protons are same but the number of neutrons vary due to which atomic masses also vary.
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i.e.
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7 0
3 years ago
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