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Scilla [17]
3 years ago
6

A ray of yellow light has a wavelength of about 5.8×10−7 m. Will exposure to yellow light cause electrons to be emitted from ces

ium?
Chemistry
1 answer:
Dima020 [189]3 years ago
8 0
Given the wavelength of the yellow light (700 nm. in this case) we can find the frequency 
<span>by dividing the speed of light c by the wavelength w, that is: f = c/w and we know that </span>
<span>c is equal to 2.998 * 10**8 meters per second. </span>
<span>So the frequency f = (2.998 * 10**8) / (7.0 * 10**-7) = 4.283 * 10**14 cycles per sec. </span>
<span>(or Hz.) Since the threshold frequency of Cs is 9.39 * 10**14 Hz, the red light doesn't </span>
<span>have a high enough frequency (or energy) to cause electron emission. </span>
<span>Hope this answers your question.</span>
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What change would shift the equilibrium system to the left?
kotegsom [21]

Answer:

C

Explanation:

sorry if its wrong but i think its right

6 0
3 years ago
Complete combustion of 4.40 g of a hydrocarbon produced 14.1 g of co2 and 5.04 g of h2o. what is the empirical formula for the h
andrew11 [14]
For a hydrocarbon, the combustion reactions are the following:

C + O₂ --> CO₂
H₂ + 1/2 O₂ --> H₂O

The molar mass of CO₂ is 44 g/mol while C is 12 g/mol. Let's solve for amount of C in hydrocarbon.

Mass of C = (14.1 g CO₂)(1mol/44g)(1 mol C/1 mol CO₂)(12 g/mol) = 3.845 g C
So, that means that the mass of hydrogen is:
Mass of H = 4.4 - 3.845 = 0.555 g

Moles C = 3.845/12 = 0.32042
Moles H = 0.555/1 = 0.555
Divide both by the smaller value, 0.32042.

C: 0.32042/0.32042 = 1
H: 0.555/0.32042 = 1.732
We have to get an answer that is closest to a whole number. Let's try multiplying both with 4.
C: 1*4 = 4
H: 1.732*4 = 6.93≈7

<em>Thus, the empirical formula is C₄H₇.</em>
3 0
3 years ago
What happens to energy when light is transmitted through or reflected off a material?
Reika [66]

Answer:

The light wave could be absorbed by the object, in which case its energy is converted to heat.

Explanation:

8 0
2 years ago
At equilibrium, both the forward reaction and the reverse reaction occur simultaneously and at the same rate. Since the rates ar
allsm [11]

Answer : The concentration of NO is, 6.8\times 10^{-3}M

Solution :  Given,

Concentration of N_2 and O_2 = 152 M

Equilibrium constant, K_c = 2.0\times 10^{-9}

The given equilibrium reaction is,

N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

The expression of K_c will be,

K_c=\frac{[NO]^2}{[N_2][O_2]}

Now put all the given values in this expression, we get:

2.0\times 10^{-9}=\frac{[NO]^2}{152\times 152}

[NO]=6.8\times 10^{-3}M

Therefore, the concentration of NO is, 6.8\times 10^{-3}M

5 0
3 years ago
The VSEPR model was developed before any xenon compounds had been prepared. Thus, these compounds provided an excellent test of
Natalka [10]

The maximum amount of XeF4 that could be produced is 0.5 moles.

XeF4 = Xe (g) 2 F2 (g) (g)

Xe and F2 have a mole ratio of 1:2. Because of this, the reaction would be limited by F2 when there is 1 mole of Xe and 1 mole of F2.

<h3>What is mole ratio?</h3>

The mole ratio is the ratio of any two compounds' mole amounts that are present in a balanced chemical reaction.

A comparison of the ratios of the molecules required to accomplish the reaction is given by the balancing chemical equation.

A mole ratio is a conversion factor used in chemical reactions to link the mole quantities of any two compounds. A conversion factor's numbers are derived from the balanced chemical equation's coefficients.

To learn more about mole ratio from the given link:

brainly.com/question/14425689

#SPJ4

6 0
2 years ago
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