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viva [34]
3 years ago
12

A person walks along a road 2 miles and rests. Then taking another road, he travels 3 miles; and switching to a dirt path, he wa

lks 2 miles before arriving at his destination. The distance the person has traveled is 7 miles. True False
Physics
2 answers:
spayn [35]3 years ago
4 0

Answer:

true

Explanation:

RoseWind [281]3 years ago
4 0

A person walks along a road 2 miles and rests. Then taking another road, he travels 3 miles; and switching to a dirt path, he walks 2 miles before arriving at his destination. The distance the person has traveled is 7 miles. The given statement is true.

Answer: True

<u>Explanation:</u>

The distance traveled by the person can be known by simply adding up the all the distances traveled by the person. That is, which gives, therefore, the total distance traveled is 7 miles and hence the given statement is true.

Distance is the measure of how long a person travels and is a scalar quantity. Therefore, total distance takes up into account all the distance traveled by a person.

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A ball bounces changing velocity from vi=15m/s[D] to vf=15m/s[U] in t=0.01s. The balls acceleration is *
fomenos

Answer:

Option (A) is correct

Explanation:

a= (vf-vi)/ t

put the values

hence,

a= ( 15-15)/0.01

a=0

5 0
3 years ago
Read 2 more answers
2 Points
yulyashka [42]

The  force applied to lift the crate is 171 N

Explanation:

The lever works on the principle of equilibrium of moments, so we can write:

F_i d_i = F_o d_o

where

F_i is the  force in input

d_i is the arm of the input force

F_o is the output force

d_o is the arm of the output force

For the lever in this problem, we have:

d_i = 0.25 m

d_o = 0.19 m

F_i = 130 N (force applied)

Solving the equation for F_o, we find the force applied to lift the crate:

F_o = \frac{F_i d_i}{d_o}=\frac{(130)(0.25)}{0.19}=171 N

Learn more about levers:

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6 0
3 years ago
Certain rifles can fire a bullet with a speed of 950 m/s just as it leaves the muzzle (this speed is called the muzzle velocity)
TiliK225 [7]

Answer:

a) By v^2 = u^2 + 2as => a= 70291.70.

(b)By v = u + at => t= 1.58 ms.

(c)By v^2 = u^2 - 2gh => H = 46045.92 m.

Explanation:

a) By v^2 = u^2 + 2as

(950)^2 = 0 + 2 \times a \times 0.75\\a = 601666.67 m/s^2\\a/g = 688858.70/9.8 = 70291.70

(b)By v = u + at

950 = 0 + 601666.67 \times t\\t = 1.58 x 10^-3 sec = 1.58 ms

(c)By v^2 = u^2 - 2gh

0 = (950)^2 - 2 \times9.8 \times H\\H = 46045.92 m

4 0
3 years ago
An object that is falling has the following type(s) of energy. Ignore air resistance.
Anton [14]
Potential and kinetic
6 0
3 years ago
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Glycerin at a temperature of 30 degrees celcius flows at a rate of 8×10−6m3/sthrougha horizontal tube with a 30mmdiameter. what
marusya05 [52]

The pressure drop in pascal is 3.824*10^4 Pascals.

To find the answer, we need to know about the Poiseuille's formula.

<h3>How to find the pressure drop in pascal?</h3>
  • We have the Poiseuille's formula,

                     Q=\frac{\pi r^4P}{8\beta l}

  • where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.
  • By substituting values and rearranging we will get the pressure drop as,

                  P=3.284Pascals

Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4.

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3 0
1 year ago
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