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viva [34]
3 years ago
12

A person walks along a road 2 miles and rests. Then taking another road, he travels 3 miles; and switching to a dirt path, he wa

lks 2 miles before arriving at his destination. The distance the person has traveled is 7 miles. True False
Physics
2 answers:
spayn [35]3 years ago
4 0

Answer:

true

Explanation:

RoseWind [281]3 years ago
4 0

A person walks along a road 2 miles and rests. Then taking another road, he travels 3 miles; and switching to a dirt path, he walks 2 miles before arriving at his destination. The distance the person has traveled is 7 miles. The given statement is true.

Answer: True

<u>Explanation:</u>

The distance traveled by the person can be known by simply adding up the all the distances traveled by the person. That is, which gives, therefore, the total distance traveled is 7 miles and hence the given statement is true.

Distance is the measure of how long a person travels and is a scalar quantity. Therefore, total distance takes up into account all the distance traveled by a person.

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choli [55]
The answer should be flammability
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How many neutrons does element X have if its atomic number is 48 and its mass number is 167?
lys-0071 [83]
If its atomic number is 48, then it has 48 protons in the nucleus
of each atom.  Any more mass than that is supplied by the neutrons
that are mixed in there with the protons.

If the mass is 167, and 48 of those are protons, then there are

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The direction of the buoyant force on an object placed in fluid is
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Question 10(Multiple Choice Worth 7 points)
nataly862011 [7]

Organisms that existed over a limited period

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Index fossils are organisms that existed within a limited period in the geologic record.

These fossils are indicator fossils that serves as guide to define the relative ages of rocks in a sequence.

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5 0
3 years ago
Two electrons are separated by a distance of 3.00 x 10^-6 meter. What are the magnitude and direction of the electrostatic force
Brilliant_brown [7]
The electrostatic force between two charges q1 and q2 is given by
F=k_e  \frac{q_1 q_2}{r^2}
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r=3.00 \cdot 10^{-6} m is the distance between the two charges.

In our problem, the two charges are two electrons, so their charges are equal and equal to 
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By substituting these values, we find the intensity of the force between the two electrons:
F=(8.99 \cdot 10^9 N m^2 C^{-2})  \frac{(-1.6 \cdot 10^{-19}C)(-1.6 \cdot 10^{-19}C)}{(3.00 \cdot 10^{-6} m)^2}=2.6 \cdot 10^{-17}N

This is the magnitude of the force each electron exerts to the other one. The direction is given by the sign of the charges: since the two electrons have same charge, they repel each other, so the force exerted by electron 1 is toward electron 2 and viceversa.
5 0
3 years ago
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