I’m almost certain it’s C
Answer: There is an unsolved mystery surrounding Titan's atmosphere: Because methane is broken down by sunlight, scientists believe there is another source that replenishes what is lost. One potential source of methane is volcanic activity, but this has yet to be confirmed.
Explanation:
Answer:
Explanation:
Polarization In this case angle of incidence is not equal to angle of polarization, hence reflected light is partially polarized and transmitted light is also partially polarized. by reflection is explained by Brewster's law,
According to this when unpolarized light incident on glass plate at an angle is called as angle of polarizing the reflected light is plane polarized, and transmitted light is partially polarized. The plane of vibration of polarized light is having plane of vibrations perpendicular to plane of incidence.
Explanation:
Given that,
(a) Speed, 
Mass of the electron, 
Mass of the proton, 
The wavelength of the electron is given by :



The wavelength of the proton is given by :



(b) Kinetic energy, 
The relation between the kinetic energy and the wavelength is given by :






Hence, this is the required solution.
Answer:
true I think
Explanation:
sorry if I'm wrong, have a good day:)