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viva [34]
2 years ago
12

A person walks along a road 2 miles and rests. Then taking another road, he travels 3 miles; and switching to a dirt path, he wa

lks 2 miles before arriving at his destination. The distance the person has traveled is 7 miles. True False
Physics
2 answers:
spayn [35]2 years ago
4 0

Answer:

true

Explanation:

RoseWind [281]2 years ago
4 0

A person walks along a road 2 miles and rests. Then taking another road, he travels 3 miles; and switching to a dirt path, he walks 2 miles before arriving at his destination. The distance the person has traveled is 7 miles. The given statement is true.

Answer: True

<u>Explanation:</u>

The distance traveled by the person can be known by simply adding up the all the distances traveled by the person. That is, which gives, therefore, the total distance traveled is 7 miles and hence the given statement is true.

Distance is the measure of how long a person travels and is a scalar quantity. Therefore, total distance takes up into account all the distance traveled by a person.

You might be interested in
What two things can happen in the life of a massive star after it passes from the supernova stage?
kupik [55]
Medium stars become dwarf stars, large stars become either neutron (pulsar) stars or black holes
4 0
3 years ago
un movil que parte del reposo alcanza una velocidad de 75 m/s en 13 segundos ¿cual su aceleracion y el espacio que recorrio en l
Dmitriy789 [7]

Answer:

Acceleration = 5.77 m/s²

Distance cover in 13 seconds = 487.56 meter

Explanation:

Given:

Final velocity of mobile device = 75 m/s

initial velocity of mobile device = 0 m/s

Time taken = 13 seconds

Find:

Acceleration

Distance cover in 13 seconds

Computation:

v = u + at

75 = 0 + (a)(13)

13a = 75

a = 5.77

Acceleration = 5.77 m/s²

s = ut + (1/2)(a)(t²)

s = (0)(t) + (1/2)(5.77)(13²)

Distance cover in 13 seconds = 487.56 meter

8 0
2 years ago
A 3-kg wheel with a radius of 35 cm is spinning in the horizontal plane about a vertical axis through its center at 800 rev/s. A
Kruka [31]

Answer:

\omega_f = 585.37 \ rev/s

Explanation:

given,

mass of wheel(M) = 3 Kg

radius(r) = 35 cm

revolution (ω_i)=  800 rev/s

mass (m)= 1.1 Kg

I_{wheel} = Mr²

when mass attached at the edge

I' = Mr² + mr²

using conservation of angular momentum

I \omega_i = I' \omega_f

(Mr^2) \times 800 = ( M r^2 + m r^2) \omega_f

M\times 800 = ( M + m )\omega_f

3\times 800 = (3+1.1)\times \omega_f

2400 = (4.1)\times \omega_f

\omega_f = 585.37 \ rev/s

3 0
3 years ago
you ride your bike for a distance of 30km. you travel ata a speed of 0.75km/minute.how many minutes does it take
mihalych1998 [28]
Distance for which the bike is ridden = 30 km
Speed at which the bike is driven = 0.75 km/minute
Let us assume the number of minutes taken to travel the distance of 30 km = x
Now we already know the formula of speed can be written as
Speed = Distance traveled/ Time taken
0.75 = 30/x
0.75x = 30
x = 30/0.75
  = 40 minutes
So the time taken for riding a distance of 30 km will be 40 minutes. I hope this procedure is simple enough for you to understand.
7 0
3 years ago
Read 2 more answers
Help plzzzz thank youu
dybincka [34]
The answer is B I hope this helps luv
5 0
3 years ago
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