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Ilia_Sergeevich [38]
3 years ago
15

What are the things on top of the titanic called?

Physics
1 answer:
KengaRu [80]3 years ago
6 0
Simple answer: they are like large chimneys for the fuel's excess gas.
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How old is the moon!
wolverine [178]

4.53 billion years

1.653 trillion days

39.68 trillion hours

2.381 × 10^15 minutes

1.429 × 10^17 seconds

5 0
3 years ago
Read 2 more answers
during convection, hot material _____ (expands & sinks, cools & rises, expands & rises, deflates & rises) then m
Lady bird [3.3K]

Answer:

During convection, hot material expands & rises then moves to the side and cools & sinks. this circular pattern is called a convection current.

Explanation:

Convection is one of the three methods of transfer of heat. It occurs only in fluids (liquids or gases).

Convection occurs when there is a source of heat that heats a fluid, such as in a boiling pot of water. The water which is on the bottom of the pot becomes warmer before than the water at the top (because it is closer to the flame), and so it becomes less dense: for this reason, it expands and it becomes rising. On the contrary, the water on top is colder, so it is more dense and starts sinking, replacing the warmer water. As the new part of water gets warmer, it starts rising, and so the process is continuously repeated. This circular current is called convection current.

4 0
3 years ago
Read 2 more answers
Can someone please help me?
Alina [70]

Answer:

D would be it

Explanation:

cause none of the rest Makes sense to the book of the picture and I'm 100% sure =)

6 0
3 years ago
A 5-g lead bullet traveling in 20°C air at 300 m/s strikes a flat steel plate and stops.
densk [106]

To solve this problem it is necessary to apply the concepts related to the Kinetic Energy and the Energy Produced by the heat loss. In mathematical terms kinetic energy can be described as:

KE = \frac{1}{2} mv^2

Where,

m = Mass

v = Velocity

Replacing we have that the Total Kinetic Energy is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (5*10^{-3})(300)^2

KE =  225J

On the other hand the required Energy to heat up t melting point is

Q_1 = mC_p \Delta T

Q_2 = L_f m

Where,

m = Mass

C_p =Specific Heat

\Delta T =Change at temperature

L_f = Latent heat of fussion

Heat required to heat up to melting point,

Q = Q_1+Q_2

Q = mC_p \Delta T+L_f m

Q = 5*0.128*(327-20) + 5*24.7

Q = 310J

The energy required to melt is larger than the kinetic energy. Therefore the heat of fusion of lead would be 327 ° C: The melting point of lead.

4 0
3 years ago
an object on a planet has a mass of 243 Kg. what is the acceleration of the object, if the radius of the planet is 2.32 x 10^7m
Ksenya-84 [330]

Answer:

7.87x10^5m/s^2

Explanation:

3 0
3 years ago
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