Question:
Mateo drew the field lines around the ends of two bar magnets but forgot to label the direction of the lines with arrows. In which direction should an arrow at position 1 point?
left
right
up
down
Answer:
The correct answer is
Left
Explanation:
Magnetic circuits describe the path of a magnetic flux. In the same way electricity follows a complete closed circuit, the path of a magnetic flux is also a complete and closed circuit which leaves from the N pole, migrates through the air and reenters the magnet through the S pole through which it passes back into the magnet to come to the N pole again.
As such the magnetic field lines emanate from the N pole which is on he right to the S pole which is on the left. Hence the arrow should point in the left direction.
It's boring.
You're forced to eat Mars Bars because it grows here.
Once in a while, a rogue Snickers Bar hurtles from asteroids.
That only happens about once a year.
(Am I funny yet? =_=)
If the spring constant of the bungee rope is greater than that of a rubber band, it will have more elastic potential energy. However, if the spring constant of the rubber band is greater than that of the bungee rope, the rubber band will have more elastic potential energy.
<h3>Elastic Potential energy </h3>
Elastic Potential energy is the stored in a elastic string which has been compressed or stretched.
The formula for calculating elastic potential energy is given as:
- Elastic Potential = 1/2 Kx^2
where
- K is the spring constant of elastic material
- x is the distance if compression or stretch
The elastic potential of an elastic material depends on the spring constant and the distance stretched or compressed.
Since the bungee rope and the rubber band are stretched the same distance, their elastic potential energy depends on their spring constant.
Therefore, if spring constant of the bungee rope is greater than that of a rubber band, it will have more elastic potential energy. However, if the spring constant of the rubber band is greater than that of the bungee rope, the rubber band will have more elastic potential energy.
Learn more about elastic potential energy at: brainly.com/question/1075827
Answer:
The current on the water layer = 1.64×10^-3A
Explanation:
Let's assume that the radius given for the string originates from the centre of the string. The equation for determining the current in the water layer is given by:
I = V × pi[(Rwater + Rstring)^2 - (Rstring)^2/ ( Resitivity × L)
I =[ 166×10^6 ×3.142[(0.519×10^-4) + (2.15×10^-3])^2 - ( 2.15×10^-3)^2] / ( 183 × 831)
I =[ 521572000(4.848×10^6)- 4.623×10^-6]/ 154566
I = 252.83 -(4.623×10^-6)/ 154566
I = 252.83/154566
I = 1.64× 10^-3A
