<h2>
The area of a triangle is =54 square units</h2><h2>
The perpendicular distance from B to AC is = 
</h2>
Step-by-step explanation:
Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)
The area of a triangle is= ![\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx_1%28y_2-y_3%29%20%2Bx_2%20%28y_3-%20y_1%29%2Bx_3%28y_1-y_2%29%5D)
=![|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|](https://tex.z-dn.net/?f=%7C%5Cfrac%7B1%7D%7B2%7D%20%5B2%282-8%2B12%288-1%29%2B12%281-2%29%5D%7C)
=
= 54 square units
The length of AC = 
= 
=
units
Let the perpendicular distance from B to AC be = x
According To Problem
⇔
units
Therefore the perpendicular distance from B to AC is =
Answer: y =7/4x
Step-by-step explanation:
The y-intercept is 0. To find the slope, do the change in y over the change in x. At the point on the graph, there is a slope of 14/8 = 7/4
Answer: Choice C
Vertex = (5, -2)
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Explanation:
Vertex form is 
where the vertex itself is located at (h,k)
As the name implies, we can very quickly pull out the coordinates of the vertex without doing much math at all.
In the case of choice C, we have 
which is the same as 
and we can see that h = 5 and k = -2. Therefore, the vertex is located at (h,k) = (5, -2)
Answer:
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Step-by-step explanation:
