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schepotkina [342]
3 years ago
14

What are the three states of matter

Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
4 0

Explanation:

C. Solid, liquid, vapor.

ArbitrLikvidat [17]3 years ago
4 0
C. Solid, liquid, vapor
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What is released during cellular respiration?
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During cellular respiration<span>, glucose is broken down in the presence of oxygen to produce carbon dioxide and water,energy is </span><span>released.</span>
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44.90 g of reactants are placed in a beaker
sergiy2304 [10]

Answer:

D. -1882J

Explanation:

We can solve the energy released in a chemical reaction in an aqueous medium using the equation:

Q = -m*C*ΔT

<em>Where Q is energy (In J),</em>

<em>m is mass of water (45.00g)</em>

<em>C is specific heat of water (4.184J/g°C)</em>

<em>And ΔT is change in temperature (25.00°C - 15.00°C = 10.00°C)</em>

<em />

Replacing:

Q = -45.00*4.184J/g°C*10.00°C

Q = -1882J

Right answer is:

<h3>D. -1882J</h3>

<em />

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3 years ago
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Apply sunscreen with a high SPF to protect your skin from UV (ultraviolet) rays
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Which substance has non polar covalent bonds
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Cl2 is the right answer since the molecule is composed of two chlorines.

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A gas exerts a pressure of 1.8 atm at a temperature of 60 degrees celsius. What is the new temperature when the pressure of the
Kamila [148]

The answer for the following problem is mentioned below.

  • <u><em>Therefore the final temperature of the gas is 740 K</em></u>

Explanation:

Given:

Initial pressure of the gas (P_{1}) = 1.8 atm

Final pressure of the gas (P_{2})  = 4 atm

Initial temperature of the gas (T_{1}) = 60°C = 60 + 273 = 333 K

To solve:

Final temperature of the gas (T_{2})

We know;

From the ideal gas equation;

we know;

P  × V = n × R × T

So;

we can tell from the above equation;

 <u>   P ∝ T</u>

(i.e.)

      <em> </em>\frac{P}{T}<em> = constant</em>

        \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1}  = initial pressure of a gas

P_{2} = final pressure of a gas

T_{1} = initial temperature of a gas

T_{2} = final temperature of a gas

        \frac{1.8}{4} = \frac{333}{T_{2} }

   T_{2} =\frac{333*4}{1.8}

    T_{2} = 740 K

<u><em>Therefore the final temperature of the gas is 740 K</em></u>

8 0
3 years ago
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