Answer:
5.12
Explanation:
5.22 x 10 - 3 = [?] x 10 - 2 (move - 2 to the other side with changed sign)
5.22 x 10 - 3 + 2 = [?] x 10 (divide both sides by 10)
[?] = (5.22 x 10 - 1) / 10
[?] = 5.12
Fermentation occur in yeast is alcoholic.
The calculated enthalpy values are as follows:
- Total enthalpy of reactants = -103.85 KJ/mol
- Total enthalpy of products = -2057.68 KJ/mol
- Enthalpy of reaction = -1953.83 kJ/mol
<h3>What is the enthalpy of the reaction?</h3>
The enthalpy of the reaction is determined as follows:
- Enthalpy of reaction = Total enthalpy of products -Total enthalpy of reactants
- Total enthalpy of reactants = (ΔHf of Reactant 1 x Coefficient) + (ΔHf of Reactant 2 x Coefficient)
- Total enthalpy of products= (ΔHf of Product 1 x Coefficient) + (ΔHf of Product 2 x Coefficient)
Equation of reaction equation: C₃H₈ (g) + 5 O(g) → 4 H₂O(g) + 3CO₂(g)
Total enthalpy of reactants = (-103.85 * 1) + (0 * 5)
Total enthalpy of reactants = -103.85 + 0
Total enthalpy of reactants = -103.85 KJ/mol
Total enthalpy of products = (-393.51 * 4) +(-241.82 * 3)
Total enthalpy of products = (-1574.04) + (-483.64)
Total enthalpy of products = -2057.68 KJ/mol
Enthalpy of reaction = -2057.68 KJ/mol -(-103.85 KJ/mol)
Enthalpy of reaction = -1953.83 kJ/mol
In conclusion, the enthalpy of the reaction is determined from the difference between the total enthalpy of products and reactants.
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Three double bonds and four single bonds, or 3(+)+4=7+3, are present in cumulene.
Sigma bond between the hydrogen and carbon on the end-side of the cumulene is visible. Carbon and hydrogen are linked by a total of four sigma bonds. Carbon is joined to carbon in the center by 3 sigma bonds and 3 pi bonds. Cumulene now has a total of 7 sigma bonds and 3 pi bonds. A cumulene is a molecule in organic chemistry that has three or more cumulative (consecutive) double bonds. sp2 hybrid orbital of C overlapping with 2p orbital of O and one bond make up the bond.
In the case of compounds with two bonds, one bond is a sigma bond and the other is a pi bond. A triple bond indicates that the chemicals.
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5.7% KCl is 94.3 % water.
Therefore, for 1000 g of water the mass of KCl will be (1000× 5.7)/94.3 = 60.445 grams.
1 mole of KCl is equal to 74.55 g,
therefore, 60.445 g will be 60.445/74.55 = 0.8108 mole of KCl
Hence, 0.8108 moles of KCl should release twice that number of moles 1.6216 moles ions.
Having 1.6216 moles of KCl ions dissolved in 1000g of water, gives us 1.6216 molar if solution.
Using the freezing point depression constant of water.
dT = Kf (molarity)
dT = (1.86 C/ molar) (1.6216 m)
dT = 3.016 C drop in freezing point
Therefore, it should freeze at - 3.016 Celsius