Is the capacity or potential to influence?

During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 * t2 to so

Ulleksa [173]

8/9 score.....................

3 0

3 years ago

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A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At

yaroslaw [1]

The electric field of a very large (essentially infinitely large) plane of charge is given by:

E = σ/(2ε₀)

E is the electric field, σ is the surface charge density, and ε₀ is the electric constant.

To determine σ:

σ = Q/A

Where Q is the total charge of the sheet and A is the sheet's area. The sheet is a square with a side length d, so A = d²:

σ = Q/d²

Make this substitution in the equation for E:

E = Q/(2ε₀d²)

We see that E is inversely proportional to the square of d:

E ∝ 1/d²

The electric field at P has some magnitude E. Now we double the side length of the sheet while keeping the same amount of charge Q distributed over the sheet. By the relationship of E with d, the electric field at P must now have a quarter of its original magnitude:

$E_{new} = E/4$

4 0

3 years ago

Water flows through a 2.5cm diameter pipe at a rate of

My name is Ann [436]

Answer:

From the Bernoulli energy principle,

ΔP + 1/2ρΔv² = 0 -------------------------- eqn 1

where

ΔP = pressure drop = P2 - P1 = (1 - 0.25)x10⁵ N/m =7.5 x 10⁴N/m

Δv²= velocity change = v₂² - v₁²

ρ = water density = 1kg/m3

Recall volumetric flow rate, Q=A v = constant

A = cross sectional area = πr²=πd²/4

d=pipe diameter at point 2 = 2.5cm = 0.025m and Q =0.20m³/min = 0.00333m³/s

So A= 0.000491m²

we can get v2 = Q/A = 6.79m/s

From eqn 1, v₁² = 2(P2 - P1)/ρ + v₂²

v₁² = (2 x 7.5 x 10⁴)/1000 + 6.79²

v₁² = 196

v₁ = 14m/s

we can now get the area of the constriction point 2, A₁ = Q/v₁

A₁ = 0.000238m² and the diameter now will be d₁

d₁² = 4 x A₁ / π

= 4 x 0.000238/3.14 = 0.000303m²

d₁ = √0.000303 = 0.0174m

Therefore, the diameter of a constriction in the pipe at the new pressure = 0.0174m = 1.74cm

6 0

3 years ago

What is the kinetic energy of an object that has a mass of 12 kg and moves with a velocity of 10 m/s

WITCHER [35]

Answer:

600 J

Explanation:

The formula to find the kinetic energy of an object is $\frac{1}{2}mV^2$

m = mass in kg
V = velocity in m/s
KE is measured in Joules just as all other forms of energy.

Now, let's plug in the variables we're given and simplify.

$\frac{1}{2}(12)(10)^2$
$\frac{1}{2}(12)(100)$
$(6)(100)$
$(600)$

Thus, the answer is 600 Joules.

6 0

3 years ago

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What were two arguments or lines of evidence in support of the geocentric model?

Inessa05 [86]

Answer:

Two arguments or lines of evidence in support of the geocentric model are:

Geocentric model: This model describe that the earth is in the center of the universe and all the planets. Moon and the sun are revolved around the earth. This model explained the predominant description.

Heliocentric model: In this model the earth and the sun are consider moving and the sun are in the center of the solar system. And the sun is at the center position where all the planets are revolving around it, being dissimilar to the geocentric model.

7 0

3 years ago