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3 years ago

What is the distance covered by a Freely falling object 5 seconds after being dropped ? After 6 seconds?

1 answer:

5 0

This year is 60 years since I learned this stuff, and one of the things I always remembered is the formula for the distance a dropped object falls:

D = 1/2 A T²

Distance = (1/2) (acceleration) (time²)

The reason I never forgot it is because it's SO useful SO often. You really should memorize it. And don't bury it too deep in your toolbox ... you'll be needing it again very soon. (In fact, if you had learned it the first time you saw it, you could have solved this problem on your own today.)

The problem doesn't tell us what planet this is happening on, so let's make it easy and just assume it's on Earth. Then the 'acceleration' is Earth gravity, and that's 9.8 m/s² .

In 5 seconds:

D = 1/2 A T²

D = (1/2) (9.8 m/s²) (5 sec)²

D = (4.9 m/s²) (25 sec²)

D = 122.5 meters

In 6 seconds:

D = 1/2 A T²

D = (1/2) (9.8 m/s²) (6 sec)²

D = (4.9 m/s²) (36 sec²)

D = 176 meters

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If an element has 2 valence electrons, how many dots will be in the elements dot diagram?

antiseptic1488 [7]

Well since we're doing the Lewis dot diagram do you know which element on the table that it is?

6 0

3 years ago

Read 2 more answers

Khalid has been studying the gravitational attraction between three pairs of objects. The table shows the distance between each

SCORPION-xisa [38]

Answer:

Explanation:

Probably the most famous force of all is gravity. We humans on earth think of gravity as an apple hitting Isaac Newton on the head. Gravity means that stuff falls down. But this is only our experience of gravity. In truth, just as the earth pulls the apple towards it due to a gravitational force, the apple pulls the earth as well. The thing is, the earth is just so massive that it overwhelms all the gravity interactions of every other object on the planet. Every object with mass exerts a gravitational force on every other object. And there is a formula for calculating the strengths of these forces, as depicted in the diagram below:

Diagram of gravitational forces between two spheres

Let’s examine this formula a bit more closely.

F refers to the gravitational force, the vector we ultimately want to compute and pass into our applyForce() function.

G is the universal gravitational constant, which in our world equals 6.67428 x 10^-11 meters cubed per kilogram per second squared. This is a pretty important number if your name is Isaac Newton or Albert Einstein. It’s not an important number if you are a ProcessingJS programmer. Again, it’s a constant that we can use to make the forces in our world weaker or stronger. Just making it equal to one and ignoring it isn’t such a terrible choice either.

m_1m

m, start subscript, 1, end subscript and m_2m

m, start subscript, 2, end subscript are the masses of objects 1 and 2. As we saw with Newton’s second law (\vec{F} = M\vec{A}

F, with, vector, on top, equals, M, A, with, vector, on top), mass is also something we could choose to ignore. After all, shapes drawn on the screen don’t actually have a physical mass. However, if we keep these values, we can create more interesting simulations in which “bigger” objects exert a stronger gravitational force than smaller ones.

\hat{r}

r, with, hat, on top refers to the unit vector pointing from object 1 to object 2. As we’ll see in a moment, we can compute this direction vector by subtracting the location of one object from the other.

r^2r

r, squared refers to the distance between the two objects squared. Let’s take a moment to think about this a bit more. With everything on the top of the formula—G, m_1m

m, start subscript, 1, end subscript, m_2m

m, start subscript, 2, end subscript—the bigger its value, the stronger the force. Big mass, big force. Big G, big force. Now, when we divide by something, we have the opposite. The strength of the force is inversely proportional to the distance squared. The farther away an object is, the weaker the force; the closer, the stronger.

Hopefully by now the formula makes some sense to us. We’ve looked at a diagram and dissected the individual components of the formula. Now it’s time to figure out how we translate the math into ProcessingJS code. Let’s make the following assumptions.

We have two objects, and:

Each object has a PVector location: location1 and location2.

Each object has a numeric mass: mass1 and mass2.

There is a numeric variable G for the universal gravitational constant.

Given these assumptions, we want to compute a PVector force, the force of gravity. We’ll do it in two parts. First, we’ll compute the direction of the force \hat{r}

r, with, hat, on top in the formula above. Second, we’ll calculate the strength of the force according to the masses and distance.

Remember when we figured out how to have an object accelerate towards the mouse? We're going to use the same logic.

4 0

3 years ago

The momentum of an object is not dependent on which one of the following quantitiesa) acceleration b) inertiac) massd) velocity

amm1812

Answer:

Inertia

Explanation:

We have to find that on which quantity the momentum of an object does not depend.

We know that

Momentum of object=mv

Where m=Mass of object

v=Velocity of object

Momentum of object depends upon mass and velocity.

When velocity of object increases then momentum is also increases.

When the mass of object is increases then the momentum of object is also increases.

If mass decreases then the momentum of object decreases.

If velocity decreases then the momentum of object decreases.

Acceleration depends on velocity because

Acceleration= $\frac{dv}{dt}$

Therefore, momentum is also depend upon the velocity.

Inertia is defined as the property of object that resist change in its motion.

Therefore, momentum does not depend on Inertia of object.

7 0

4 years ago

Which is more dangerous to living things: gamma rays or X-rays?

Dima020 [189]

Answer:

gamma

Explanation:

x rays are often used in hospitals

gamma rays :

are highly penetrating

have highly energetic ionizing radiation

frequency is higher

wavelengths are shorter rays

can attack DNA and break the strands of that essential biological molecule

quizlet

brainly.com/question/13047731

quora

6 0

2 years ago

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An airplane of mass 1.60 ✕ 104 kg is moving at 66.0 m/s. The pilot then increases the engine's thrust to 7.70 ✕ 104 N. The resis

Ivan

(a) No, because the mechanical energy is not conserved

Explanation:

The work-energy theorem states that the work done by the engine on the airplane is equal to the gain in kinetic energy of the plane:

$W=\Delta K$ (1)

However, this theorem is only valid if there are no non-conservative forces acting on the plane. However, in this case there is air resistance acting on the plane: this means that the work-energy theorem is no longer valid, because the mechanical energy is not conserved.

Therefore, eq. (1) can be rewritten as

$W=\Delta K + E_{lost}$

which means that the work done by the engine (W) is used partially to increase the kinetic energy of the airplane ( $\Delta K$ ) and part is lost because of the air resistance ( $E_{lost}$ ).

(b) 77.8 m/s

First of all, we need to calculate the net force acting on the plane, which is equal to the difference between the thrust force and the air resistance:

$F=7.70\cdot 10^4 N - 5.00 \cdot 10^4 N=2.70\cdot 10^4 N$