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Serggg [28]
3 years ago
14

A piece of potassium metal is added to water in a beaker. The reaction that takes place is 2K(s) 2H20(/) ..... 2KOH(aq) H2(g) Pr

edict the signs of w, q, liU, and /iH
Chemistry
1 answer:
kakasveta [241]3 years ago
4 0

Answer:

Explanation:

The given reaction is exothermic . So ΔH is negative .

Gas is evolving so work done by gas is positive or w is positive.

Change in internal energy that is ΔU is negative.

q = u - w

u is negative , w is positive so q is negative .

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Please help Please help
alexdok [17]
Follow Avogadro’s Number
1 mole = 6.02 x 10^23
So we can do it
4.77x10^25/6.02x10^23 = 79.2 mole
5 0
2 years ago
Consider the equilibrium: HCOOH(aq) + F-(aq) <----> HCOO-(aq) + HF (aq) Given that the Ka of HCOOH = 1.8 x 10-4 and the Ka
Aleks [24]

Hey there!:

K = Ka * Kb / Kw

Ka = 1.8*10⁻⁴

Kb = 10⁻¹⁴ / 6.8*10⁻⁴

K =  1.8*10⁻⁴ * ( 10⁻¹⁴/ 6.8*10⁻⁴ ) * ( 1 / 10⁻¹⁴ )

K =  = 1.8 / 6.8

K = 0.265

Answer A

Therefore:

K is less than on the forward reaction is not favorable .


Hope That helps!

8 0
3 years ago
Use condensed electron configurations and Lewis electron-dot symbols to depict the ions formed from each of the following atoms,
Dennis_Churaev [7]

The formula for Cs and S is Cs₂S.

For Cs and S,

Ions formed will be Cs⁺ and S²⁻

As cesium belongs to group 1A and sulfur belongs to group 6A. Therefore, the condensed electronic configuration is -

For Cs is [Xe} 6s¹ and for S is [Ne] 3s²3p⁴.

Cs have 1 valence electron and S have 6 valence electrons.

Hence to attain a stable electronic configuration, both two Cs atoms lose one electron and form Cs⁺ and these two electrons will be accepted by one S atom to form S²⁻.

Therefore the formula for the compound is Cs₂S as Cs donate 1 electron and S will accept 2 electrons from Cs.

The formula is Cs₂S.

To learn more about electronic configuration, visit: brainly.com/question/15051483

#SPJ4

6 0
1 year ago
State whether the sign of the entropy change expected for each of the following processes will be positive or negative, and expl
Strike441 [17]

Answer:

a) ΔS is negative

b) ΔS is positive

c) ΔS is positive

d) ΔS is negative

Explanation:

Entropy (S) is a thermodynamic parameter which measures the randomness or the disorder in a system. Greater the disorder more positive will be the value of entropy.

The extent of disorder increases as substances transition from the solid to the gaseous state. i.e.

S(solid) < S(liquid) < S(gas)

The entropy change for a given reaction is:

\Delta S = S(products)-S(reactants)----(1)

a) PCl3(l) + Cl2(g) \rightarrow PCl5(s)

Here  the reactants are in the liquid and gas phase which have higher entropy than the product which is in the solid phase i.e. lower entropy.

Since S(product) < S(reactant), based on equation 1, ΔS will be negative.

b) 2HgO(s) \rightarrow 2Hg(l) + O2(g)

Here the products are in the liquid and gas phase which have higher entropy than the reactant which is in the solid phase i.e. lower entropy.

Since S(product) > S(reactant), based on equation 1, ΔS will be positive.

c) H2(g) \rightarrow 2H(g)

Here the products and reactants are in the gas phase. However the number of moles of products is greater than the reactants

Since S(product) > S(reactant), based on equation 1, ΔS will be positive.

d) U(s) + 3F2(g) \rightarrow UF6(s)

Here  one of the reactants is in the gas phase which corresponds to a more positive entropy compared to the  product which is in the solid phase i.e. lower entropy.

Since S(product) < S(reactant), based on equation 1, ΔS will be negative.

8 0
3 years ago
Write the trigonometric equation for the function with a period of 6. The function has a maximum of 3 at x = 2 and a low point o
White raven [17]

Answer:

Do you have a picture?

Explanation:

Sometimes, pictures are required to answer questions.

7 0
3 years ago
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