The required volume of 0.10M NaOH solution that student will add is 20 mL.
<h3>How do we calculate the volume?</h3>
Volume of any solution which is required to prepare buffer will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
- M₁ & V₁ are the molarity and volume of NaOH solution.
- M₂ & V₂ are the molarity and volume of HF solution.
On putting values, we get
V₁ = (0.1)(20) / (0.1) = 20mL
Hence required volume of NaOH solution is 20mL.
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Answer:
The balanced equation would be 2H2 + O2 -> 2H2O
Explanation:
To calculate the number of moles, the equation is mass of substance divided by the molar mass of substance.
Molar mass of Fe2O3 is the relative atomic mas of all the elements from the substance added up, which makes 55.845x2 + 16.0 x3 = 159.69g mol-1
So the number of moles is
545g / 159.69gmol-1
=3.41 mol (corrected to 3 sig. fig.)