What is the STANDARD unit of measurement for velocity in Physics?

Sand on a beach is covered by other layers of sand over time. The extra layers compress the first layer, packing it tighter and

klio [65]

Sandstone can be classified as sedimentary rock. Hope this helps :) If you have any more questions I'm happy to try and help.

3 0

3 years ago

The sharper the sound is the smaller the frequency of a vibrating body true or false

natima [27]

Answer:
True....
Explanation:
Amplitude determines the loudness of sound. Loudness is proportional to the square of the amplitude of the vibrating body which produces sound. ... Less the frequency, deep is the sound.

4 0

3 years ago

The picture below shows the setup for an experiment involving a 1000 mL beaker, sitting on a burner, filled with 500 mL of water

Vlad1618 [11]

Answer:

bye

Explanation:

bye

4 0

4 years ago

Two astronauts are working on the lunar surface to install a new telescope. The acceleration due to gravity on the moon is only

nydimaria [60]

Answer:

Its velocity and acceleration are both nonzero.

Explanation:

The path of the wrench is trajectory while the acceleration due to Moon's gravity is acting on it.

As the velocity follows the path, as soon as it reaches maximum height, the vertical component of velocity is zero but the horizontal component is still there, constant.

3 0

3 years ago

Suppose a child drives a bumper car head on into the side rail, which exerts a force of 3900 N on the car for 0.55 s. Use the in

-Dominant- [34]

Answer:

The impulse is 2145 kg-m/s

The final velocity is -8.34 m/s or 8.34 m/s in he opposite direction.

Explanation:

Force on the rail = 3900 N

Elapsed time of impact = 0.55 s

Impulse is the product of force and the time elapsed on impact

I = Ft

I is the impulse

F is force

t is time

For this case,

Impulse = 3900 x 0.55 = 2145 kg-m/s

If the initial velocity was 2.95 m/s

and mass of car plus driver is 190 kg

neglecting friction, the initial momentum of the car is given as

P = mv1

where P is the momentum

m is the mass of the car and driver

v1 is the initial velocity of the car

initial momentum of the car P = 2.95 x 190 = 560.5 kg-m/s

We know that impulse is equal to the change of momentum, and

change of momentum is initial momentum minus final momentum.

The final momentum = mv2

where v2 is the final momentum of the car.

The problem translates into the equation below

I = mv1 - mv2

imputing values, we have

2145 = 560.5 - 190v2

solving, we have

2145 - 560.5 = -190v2

1584.5 = -190v2

v2 = -1584.5/190 = -8.34 m/s

6 0

4 years ago