The change in momentum is 5500 kg m/s
Explanation:
The change in momentum of an object is given by
![\Delta p = m(v-u)](https://tex.z-dn.net/?f=%5CDelta%20p%20%3D%20m%28v-u%29)
where
m is the mass of the object
v is the final velocity
u is the initial velocity
In this problem, we have:
(mass of the motorcycle)
(final velocity)
(initial velocity)
Therefore, the change in momentum is
![\Delta p=(2.50\cdot 10^2)(28.0-6.0)=5500 kg m/s](https://tex.z-dn.net/?f=%5CDelta%20p%3D%282.50%5Ccdot%2010%5E2%29%2828.0-6.0%29%3D5500%20kg%20m%2Fs)
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Answer:
step bro was stuck on the elevator
Explanation:
<u>First Symbol </u>: Cobalt (Co)
Its Group Number - 9
Its Period Number - 4
Its Family Name - Transition Metal
<u>Second Symbol</u> : Silicon (Si)
Its Group Number - 14
Its Period Number - 2
Its Family Name - Semiconductor
<u>Third Symbol</u> : Astatine (At)
Its Group Number - 17
Its Period Number - 6
Its Family Name - Halogen
<u>Fourth Symbol </u>: Magnesium (Mg)
Its Group Number - 2
Its Period Number - 3
Its Family Name - Alkaline Earth Metal
<u>Fifth Symbol</u> : Xenon (Xe)
Its Group Number - 18
Its Period Number - 5
Its Family Name - Noble Gas
The momentum would increase assuming the velocity stays the same. P=Mv