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aliya0001 [1]
3 years ago
12

What type of force are you exerting when you stomp your foot on the ground

Physics
2 answers:
Hitman42 [59]3 years ago
4 0

Compression.......................

madam [21]3 years ago
3 0

Answer:

stomp???, frictional force

Explanation:

this allow ur foot to be stomp

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A dragster and driver together have mass 931.9 kg . The dragster, starting from rest, attains a speed of 25.7 m/s in 0.57 s. Fin
Mama L [17]

Answer:

45.09 m/s^2

Explanation:

from the question we were given the following parameters

mass = 931.9 kg

initial velocity (V1) = 0 m/s ( since it started from rest )

final velocity (V2) = 25.7 m/s

time (t) = 0.57 s

The average acceleration is given by:

a = ( V2 - V1 ) / t

therefore

a = (25.7 - 0) / 0.57 = 45.09 m/s^2

7 0
3 years ago
What is an example of a non contact force
olchik [2.2K]

Answer: Gravitational force

Explanation:

A non contact force can be described as a force applied to an object by another body that is not in direct contact with it.

For example, an object thrown upwards will return back due to the force of gravity acting on it. So, it means Gravitational force is acting on the body without necessarily being in contact with that body.

8 0
3 years ago
If you doubled the load resistor in a Wheatstone bridge, the load current would not be half as much. Why not?
Fofino [41]
Doubling the size of a load resistor increases the load current. Increasing the load resistance, in turn the total circuit resistance is reduced. The load current would not be half as much since when you increase the size of load resistor then load current increases.
6 0
3 years ago
What magnitude charge creates a 1.0 n/c electric field at a point 1.0 m away?
Stolb23 [73]

Answer:

1.1\cdot 10^{-10}C

Explanation:

The electric field produced by a single point charge is given by:

E=k\frac{q}{r^2}

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

In this problem, we have

E = 1.0 N/C (magnitude of the electric field)

r = 1.0 m (distance from the charge)

Solving the equation for q, we find the charge:

q=\frac{Er^2}{k}=\frac{(1.0 N/c)(1.0 m)^2}{9\cdot 10^9 Nm^2c^{-2}}=1.1\cdot 10^{-10}C

8 0
3 years ago
What is the momentum of a 750kg car traculing at a velocity of 24m/s
m_a_m_a [10]
The answer is 18000 kgm/s

Momentum is mass times velocity so just do 750•24.
7 0
3 years ago
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