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KonstantinChe [14]
3 years ago
10

The electrode that contains the item to be electroplated a) anode b)cathode

Chemistry
1 answer:
cricket20 [7]3 years ago
5 0
The answer is A, anode
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At room temperature, 20ÁC, water (H2O) is a liquid and oxygen (O2) is a gas. Based on kinetic molecular theory, which answer bes
vaieri [72.5K]
<span>Water molecules have a lower boiling temperature than oxygen molecules, so at room temperature they exist as a liquid rather than a gas.
hope it helps
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6 0
3 years ago
Draw a mechanism for the reaction of methylamine with 2-methylpropanoic acid. Draw any necessary curved arrows. Show the product
Nitella [24]

Answer:

See figure 1

Explanation:

On this case we have a <u>base</u> (methylamine) and an <u>acid</u> (2-methyl propanoic acid). When we have an acid and a base an <u>acid-base reaction </u>will take place, on this specific case we will produce an <u>ammonium carboxylate salt.</u>

Now the question is: <u>¿These compounds can react by a nucleophile acyl substitution reaction?</u> in other words <u>¿These compounds can produce an amide? </u>

Due to the nature of the compounds (base and acid), <u>the nucleophile</u> (methylamine) <u>doesn't have the ability to attack the carbon</u> of the carbonyl group due to his basicity. The methylamine will react with the acid-<u>producing a positive charge</u> on the nitrogen and with this charge, the methylamine <u>loses all his nucleophilicity.</u>

I hope it helps!

5 0
3 years ago
A 500-kg elevator is raised to a height of 10 min 10 seconds. Calculate the power of the motor.
nataly862011 [7]
Answer: 49,000 W

Explanation:
3 0
3 years ago
Draw the structure of the following three isomeric esters with chemical formula C7H12O2. Ester #1: methyl 1-methylcyclobutanecar
marissa [1.9K]

Answer:

The following three isomeric structure are given below.

Explanation:

Structure of the following three isomeric esters with chemical formula C₇H₁₂O₂

Ester #1: methyl 1-methylcyclobutanecarboxylate

Ester #2: (E)-methyl 3-methyl-3-pentenoate

Ester #3: isopropyl 2-methylpropenoate                

6 0
3 years ago
An analytical chemist is titrating of a solution of nitrous acid with a solution of . The of nitrous acid is . Calculate the pH
Burka [1]

Answer:

pH = 2.69

Explanation:

The complete question is:<em> An analytical chemist is titrating 182.2 mL of a 1.200 M solution of nitrous acid (HNO2) with a solution of 0.8400 M KOH. The pKa of nitrous acid is 3.35. Calculate the pH of the acid solution after the chemist has added 46.44 mL of the KOH solution to it.</em>

<em />

The reaction of HNO₂ with KOH is:

HNO₂ + KOH → NO₂⁻ + H₂O + K⁺

Moles of HNO₂ and KOH that react are:

HNO₂ = 0.1822L × (1.200mol / L) = <em>0.21864 moles HNO₂</em>

KOH = 0.04644L × (0.8400mol / L) = <em>0.0390 moles KOH</em>

That means after the reaction, moles of HNO₂ and NO₂⁻ after the reaction are:

NO₂⁻ = 0.03900 moles KOH = moles NO₂⁻

HNO₂ = 0.21864 moles HNO₂ - 0.03900 moles = 0.17964 moles HNO₂

It is possible to find the pH of this buffer (<em>Mixture of a weak acid, HNO₂ with the conjugate base, NO₂⁻), </em>using H-H equation for this system:

pH = pKa + log₁₀ [NO₂⁻] / [HNO₂]

pH = 3.35 + log₁₀ [0.03900mol] / [0.17964mol]

<h3>pH = 2.69</h3>
8 0
4 years ago
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