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frozen [14]
3 years ago
6

What are two ways you can increase the magnetic field of an electromagnetic?

Physics
1 answer:
lawyer [7]3 years ago
3 0

1).  Wind more turns of wire in the coil around the core.

2).  Increase the electrical current flowing in the wire.
(You can do that by using a battery or power supply with a little more voltage.)

3).  If the core of the electromagnet is anything else but pure iron,
take it out, throw it away, and replace it with a core of pure iron.
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The average, year-after-year conditions of temperature, precipitation, winds, and cloud in an area are known as its
STatiana [176]

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a. global warming

Explanation:

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3 years ago
A cable raises a mass of 198.0 kg with an acceleration of 1.2 m/s2. What force (in N) of tension is in the cable
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4 0
2 years ago
If a hot air balloon is seen rising above the top of a hill, what is the top of the hill called? Question 2 options: delta point
timofeeve [1]

If a hot air balloon has shown rising above the top of a hill, the top of the hill is considered as a reference point.

<h2>Reference Point:</h2>

It is a point that is used to standardize a experiment. The reference point is a constant point.

In the given problem:

  • The hot air balloon is rising above the top of the hill. Here, the hill is a standard point that has a fixed (constant) height.
  • Some other reference points are the top of the Eifel Tower or a famous shop which a person use to denote a certain distance.

Therefore, "If a hot air balloon has shown rising above the top of a hill" the top of the hill is considered as a reference point.

Learn more about Reference Point:

brainly.com/question/1674904

5 0
2 years ago
An object moving with a speed or 67m/s and has kinetic energy of 500 J what is the mass of the object
saveliy_v [14]
To solve this equation, simply plug the values into the equation for calculating kinetic energy.

KE = 1/2mv^2
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500 =2244.5m
m = 500/2244.5 = 0.222 kg.
8 0
3 years ago
Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150
Sever21 [200]

Answer:2.89\approx 2.9^{\circ}C/s

Explanation:

Given

Power\left ( P\right )=150 MW

mass of core\left ( m\right )=1.60\times 10^5 kg

Average specific heat \left ( C\right )=0.3349 KJ/kg^{\circ}C

And rate of increase of temperature =\frac{\mathrm{d}T}{\mathrm{d} t}

Now

P=mc\frac{\mathrm{d}T}{\mathrm{d} t}

150\times 10^6=1.60\times 10^5\times 0.3349\times \frac{\mathrm{d}T}{\mathrm{d} t}

Thus \frac{\mathrm{d}T}{\mathrm{d} t}=[tex]\frac{1.60\times 10^5\times 0.3349}{150\times 10^6}

\frac{\mathrm{d}T}{\mathrm{d} t}=2.89\approx 2.9^{\circ}C/s

6 0
3 years ago
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