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frozen [14]
2 years ago
6

What are two ways you can increase the magnetic field of an electromagnetic?

Physics
1 answer:
lawyer [7]2 years ago
3 0

1).  Wind more turns of wire in the coil around the core.

2).  Increase the electrical current flowing in the wire.
(You can do that by using a battery or power supply with a little more voltage.)

3).  If the core of the electromagnet is anything else but pure iron,
take it out, throw it away, and replace it with a core of pure iron.
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what is the approximate weight of a 20-kg cannonball on the moon if the acceleration due to gravity is 1.6m/s^2
monitta
On Earth, a cannonball with a mass of 20 kg would weigh 196 Newtons.
With the formula F=mg, where F is the weight in Newtons, m is the mass, and g is the acceleration due to gravity on the Earth which is 9.8m/s^2.
F=20kg x 9.8m/s^2= 196 Newtons

BUT on the moon, acceleration due to gravity is 1.6 m/s^2,
so F=mg=20kgx1.6m/s^2= 32 N
5 0
3 years ago
20. A mass of gas has a volume of 4 m3, a temperature of 290 K, and an absolute pressure of 475 kPa. When the gas is allowed to
aliina [53]
Given:\\V_1=4m^3\\T_1=290K\\p_1=475kPa\\\\V_2=6.5m^3\\T_2=277K\\\\Find:\\p_2=?\\\\Solution:\\\\ \frac{pV}{T} =const.\\\\ \frac{p_1V_1}{T_1} = \frac{p_2V_2}{T_2} \\\\\frac{p_1V_1T_2}{T_1}=p_2V_2\\\\\frac{p_1V_1T_2}{T_1V_2}=p_2\\\\p_2=p_1 \frac{V_1}{V_2}  \frac{T_2}{T_1} \\\\\\p_2=475kPa\cdot  \frac{4m^3}{6.5m^3} \cdot  \frac{277K}{290K} \approx 279.2kPa\\\\Correct\;is\;answer\;\;C
7 0
2 years ago
While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the
statuscvo [17]
When Alana moving 19km/h, a stationary object will be perceived by her as moving toward her with 19km/h velocity. If the object is not stationary(velocity isn't zero), the speed will increase by the object velocity.

the relative speed of the tennis ball=
the speed of Alana + true speed of the tennis ball
19km/h+ 11km/h= 30km/h
3 0
3 years ago
Read 2 more answers
In 10 seconds a car accelerates 4/ms to 60m/s. how fast was the car going before it accelerated?
SVETLANKA909090 [29]
Well it seems like this problem gives you what you need.  You said the car was going 4m/s and then accelerated to 60m/s... so 4m/s would be your answer for the initial velocity
6 0
2 years ago
Read 2 more answers
Wile E. Coyote stands on top of a 90-meter high cliff, looking down at the Roadrunner. If
Lina20 [59]

Answer:

33.516 kJ

Explanation:

Potential energy is given by:

PE = mgh

Where m is the mass, g is acceleration due to gravity, and h is the height. In this case:

PE = 38kg x 9.8m/s^2 x 90m = 33516 kg m^2/s^2 = 33516 J = 33.516 kJ

6 0
3 years ago
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