Determine the oxidation number of sodium in Na202
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Answer:
The degree of dissociation of acetic acid is 0.08448.
The pH of the solution is 3.72.
Explanation:
The
The value of the dissociation constant =
Initial concentration of the acetic acid = [HAc] =c = 0.00225
Degree of dissociation = α
Initially
c
At equilibrium ;
(c-cα) cα cα
The expression of dissociation constant is given as:
Solving for α:
α = 0.08448
The degree of dissociation of acetic acid is 0.08448.
The pH of the solution ;