Forces and Motion, Space and Time, Energy, and Nature of Matter
The volume of carbon dioxide that will be produced is 191.4 g.
Calculation:
The following is the balanced equation for the given reaction:
Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g),
It is obvious that when 1.0 mole of Fe2O3 reacts with 3.0 mole of CO, 2.0 mole of Fe and 3.0 mole of CO2 are produced.
Hence by using cross multiplication:
If 2.0 mol of Fe was produced with → 3.0 mol of CO₂, from stoichiometry.
Then how many moles of CO₂ are produced by 2.9 mol of Fe?
To find the answer we have a formula:
∴ The no. of moles of CO₂ produced = (3.0 mol)(2.9 mol)/(2.0 mol) = 4.35 mol.
∴ The mass of CO₂ produced = no. of moles x molar mass = (4.35 mol)(44.0 g/mol) = 191.4 g.
Learn more about the balanced reaction here:
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In order to compute the total hydrogen atoms present, we must first write the molecular formulas of ammonia and water to know how many hydrogen atoms are present in each molecule.
Water - H₂O; so 2 hydrogen atoms per molecule of water
Ammonia - NH₃; so 3 hydrogen atoms per molecule of ammonia
Total hydrogen atoms = 2 * molecules of water + 3 * molecules of ammonia
H atoms = 2 * 1.5 x 10²⁵ + 3 * 8.2 x 10²⁴
H atoms = 5.46 x 10²⁵
There are a total of 5.46 x 10²⁵ hydrogen atoms in the solution
