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Elodia [21]
3 years ago
10

We tend to feel less _____ when more people are around to help out. compassionate conformity responsible no answer is correct

Physics
1 answer:
never [62]3 years ago
5 0
Responsible  because we feel less stressed when others help out with our responsibilities. 
               
                 
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physics a flower pot falls from a windowsill 25.0m above the sidewalk. how much time does a passerby on the sidewalk below have
Usimov [2.4K]
v_f^2 = v_0^2 + 2*a*d
Since the flower pot is dropped, it has an initial velocity of zero. Also the flower pot accelerates due to gravity.

so

v_f = \sqrt{2*g*d}=\sqrt{2*9.81*25.0}
8 0
3 years ago
Which statement correctly compares sound and light waves ​
kolbaska11 [484]

Answer:

Light waves carry energy parallel to the motion of the wave, while sound waves carry energy perpendicular to it. Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.

Explanation:

8 0
3 years ago
Which are the simplest pure substances that cannot be broken down into any other substances
Veseljchak [2.6K]
The simplest pure substances that cannot be broken down into any other substances are elements, such as gold (Au) or oxygen (O).
6 0
3 years ago
To understand the formula for power radiated in the form of electromagnetic energy by an object at nonzero temperature. every ob
lbvjy [14]

As per Stefan - Boltzmann law we know that

1. Power radiated in the form of electromagnetic energy by an object at nonzero temperature.

2. Every object at absolute (kelvin) temperature t will radiate electromagnetic waves.

3. This radiation is typically in the infrared for objects at room temperature, with some visible light emitted for objects heated above 1000 k.

4. The formula governing the rate of energy radiation from a surface is given by p=eσat^4,

where p is the thermal power (also known as the heat current h).

Thermal radiation in visible light can be seen on hot metalwork. Its emission in the infrared is invisible to the human eye. Infrared cameras are capable of capturing this infrared emission.

Thermal radiation is electromagnetic radiation generated by the thermal motion of charged particles in matter. All matter with a temperature greater than absolute zero emits thermal radiation. Particle motion results in charge-acceleration or dipole oscillation which produce electromagnetic radiation.

Examples of thermal radiation include the visible light and infrared light emitted by an incandescent light bulb, the infrared radiation emitted by animals that is detectable with an infrared camera, and the cosmic microwave background radiation. Thermal radiation is different from thermal convection and thermal conduction—a person near a raging bonfire feels radiant heating from the fire, even if the surrounding air is very cold.

Sunlight is part of thermal radiation generated by the hot plasma of the Sun. The Earth also emits thermal radiation, but at a much lower intensity and different spectral distribution. The Earth's absorption of solar radiation, followed by its outgoing thermal radiation, are the two most important processes that determine the temperature and climate of the Earth in most climate models.

So the correct answer which is applicable here will be

This formula applies to any object of total surface area a, kelvin temperature t, and emissivity e

here

\sigma[\tex] = stefan boltzmann constant = [tex]5.67 * 10^{-8}

3 0
3 years ago
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6
lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

I = \frac{P_{avg}}{A}

I = \frac{P_{avg}}{4\pi r^2}

I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m

I = 6.529*10^{-6}W/m^2

The amplitude of electric field at the receiver is

I = \frac{E_{max}^2}{2\mu_0 c}

E_{max}= \sqrt{2I\mu_0 c}

The amplitude of induced emf by this signal between the ends of the receiving antenna is

\epsilon_{max} = E_{max} d

\epsilon_{max} = \sqrt{2I \mu_0 cd}

Here,

I = Current

\mu_0 = Permeability at free space

c = Light speed

d = Distance

Replacing,

\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}

\epsilon_{max} = 0.05434V

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

6 0
3 years ago
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