Answer:
<em>The height of water in the column = 348.14 cm</em>
Explanation:
<em>Pressure:</em><em>This is defined as the ratio of the force acting normally ( perpendicular) to the area of surface in contact. The S.I unit of pressure is N/m²</em>
<em>p = Dgh............... Equation 1</em>
<em>Where p = pressure, D = density, g = acceleration due to gravity, h = height.</em>
<em>From the question, the same pressure will support the column of mercury and water.</em>
<em>p₁ = p₂</em>
<em>Where p₁ = pressure of mercury, p₂ = pressure of water</em>
D₁gh₁ = D₂gh₂.................. Equation 2
making h₂ the subject of equation 2
h₂ = D₁gh/D₂g............... Equation 3
Where D₁ and D₂ = Density of mercury and water respectively, h₁ and h₂ = height of mercury and water respectively
Given: D₁ = 13.6 g/cm³, D₂ = 1.00 g/cm³, h₁ = 256 mm = 25.6 cm.
Constant: g = 9.8 m/s²
Substituting these values into Equation 3,
h₂ = (13.6×9.8×25.6)/1×9.8
<em>h₂ = 348.14 cm</em>
<em>The height of water in the column = 348.14 cm</em>
