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asambeis [7]
3 years ago
5

Giraffes with short necks lived in arid regions. Over time, grasses disappeared, forcing giraffes to eat from trees. Mutations i

n the genome led to some giraffes inheriting the trait for long necks. Over time, there were more giraffes with long necks in the region. What are the two reasons for the change in the population of giraffes? (More than one answer)
- adaptation?
- artificial selection?
- natural selection?
- harmful genetic traits?
Chemistry
2 answers:
Tcecarenko [31]3 years ago
8 0
I think it would be adaptation and natural selection because both the terms are when an animal adapts to their environment. I hope this helps!
Trava [24]3 years ago
5 0

Answer: adaptation

natural selection

Natural selection refers to the differential survival of the organisms in the population. It describe the fact that individual that have favorable phenotypic characteristics have better chances of survival over others in the changing environment. Adaptation is a genetic change or mutation that helps organism to survive in it's ecological niche. Due to the helpful nature of these genetic changes they are passed down from one generation to the next generation and favors the survival and abundance of a species.

Adaptation and natural selection has resulted in the change in the population of the giraffes. The giraffes being in short neck adapted the increase in neck length with an effort to obtain leaves from tall tries. The long neck giraffe got the better chances of survival and reproduction, due to natural selection the trait was passed on to generation. This resulted in the evolution of long neck giraffe species.

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Answer:

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Explanation:

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Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and
Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃

This means,

1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide

Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%

Then,

Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%

Percent\ yield\ of\ copper\ hydroxide= 84\%

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

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