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slavikrds [6]
2 years ago
5

Copper conducts heat well.

Chemistry
2 answers:
Oxana [17]2 years ago
7 0

I dont understand , what u write

Mumz [18]2 years ago
4 0

Answer:

Both of them are Physical

Explanation:

the top answer is a new level of dumb

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Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict whet
Sloan [31]

The given reaction is as follows:

2NO (g) + O₂ (g) = 2NO₂ (g), ΔH = -114 kJ

It is known that dSsurr = -dHsys / T (Temp = 355 K)

So,  dSsurr = - (-114 × 1000) / 355

dSsurr = +321.12 J/K

Hence, the value of dSsurr is +321.12 J/K

For a reaction to be spontaneous, dG<0,

Also dStotal = dSsys + dSsurr > 0

It is known that dG = dHsys - TdSsys,

Now let us assume,

dG<0

Also, dStotal = dSsys + dSsurr > 0

(-114 × 1000) - (355 × dSsys) <0

355 × dSsys > -114 × 1000

dSsys > -321

dSsys >dSsurr

dSsys + dSsurr > 0

dStotal > 0

Thus, the assumption is correct, and the given reaction is spontaneous. Hence, the final answer is Ssurr = +321 J/K reaction is spontaneous.



8 0
3 years ago
How many molecules (or formula units) are in 138.56 g C4H10 Express your answer using four significant figures.
Semenov [28]

Answer:

dont buy cheap and off we went

7 0
3 years ago
If the reduction reaction has a reduction potential of 0.1 V, and the oxidation reaction has a reduction potential of -0.4V, and
aleksley [76]

Answer : The value of ΔG expressed in terms of F is, -1 F

Explanation :

First we have to calculate the standard electrode potential of the cell.

E^o=E^o_{cathode}-E^o_{anode}

or,

E^o=E^o_{reduction}-E^o_{oxidation}

E^o=(0.1V)-(-0.4V)=+0.5V

Now we have to calculate the standard cell potential.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant

E^o = standard e.m.f of cell = +0.5 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times F\times 0.5)

\Delta G^o=-1F

Therefore, the value of ΔG expressed in terms of F is, -1 F

5 0
3 years ago
What is the mass in grams of one mole of many of any substance known as
OLEGan [10]
The molecular weight of the substance.
7 0
3 years ago
When 1.82 moles of HCL reacts with excess MnO2, how many moles of Cl2 form
s2008m [1.1K]

The balanced reaction is:<span>

MnO2(s) + 4HCl(aq) → Cl2(g) + MnCl2(aq) + 2H2O(l)

We are given the amount of hydrochloric acid to be used for the reaction. This will be the starting point for the calculations.

1.82 mol HCl ( 1 mol Cl2 / 4 mol HCl) = 0.46 mol Cl2

<span>Therefore, 0.46 mol of chlorine gas is produced for the reaction of hydrochloric acid and manganese oxide.</span></span>

5 0
3 years ago
Read 2 more answers
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