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const2013 [10]
3 years ago
9

An industrial producer is searching for a supplier for ball bearings. Its three most important supplier criteria are price, qual

ity, and delivery reliability. The firm has decided that quality and delivery reliability should carry the same weight, and that each of them are twice as important as price. If the weights sum to 100%, what would a supplier with ratings of 40, 90, and 75 in the three respective categories score as a weighted total?
Mathematics
1 answer:
Bess [88]3 years ago
8 0

Answer:

74%

Step-by-step explanation:

Let the weight of price = y%

The weight of quality = 2y%

The weight of delivery reliability = 2y%

Since the sum total of the weights is  100, it implies that:

y% + 2y% + 2y% = 100%

5y%  = 100%

y = 100/5

y = 20

So the respective weights are as below:

Price = 20%

Quality = 40%

Delivery reliability  = 40%

Weight score = score x category weight

For the supplier:

Price score = 40

Quality score = 90

Delivery reliability  score= 75

Overall weighted score = (Price score  x Price weight) + (Quality score x Quality weight) + (Delivery reliability score x delivery reliability weight)----- (1)

Substituting into (1), we have :

Overall weighted score = (40 x  20%) + (90 x 40%) + (75 x 40%)

                                       =     8 +36 +30

                                       = 74%

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Write a rule for the nth term of the sequence.
Helga [31]

Answer:

The rule for given sequence is: a_n = -27+16n

And the 100th term is: 1573

Step-by-step explanation:

Given sequence is:

-11, 5, 21, 37, 53, ...

Here

a_1 = -11\\a_2 = 5\\a_3 = 21\\a_4 = 37

First of all, we have to find if this is an arithmetic sequence

For that purpose, the common difference has to be found. Common difference, denoted by d, is the difference between consecutive terms of an arithmetic sequence

So,

d = a_2 -a_1 = 5-(-11) = 5+11 = 16\\d = a_3 -a_2 = 21-5 = 16\\d = a_4-a_3 = 37-21 = 16

As the common difference is same, the sequence is an arithmetic sequence

General rule for arithmetic sequence is:

a_n = a_1+(n-1)d

Putting values

a_n = -11+(n-1)(16)\\a_n = -11+16n-16\\a_n = -27+16n

For 100th term,

Putting n=100

a_{100} = -27+16(100)\\a_{100} = -27+1600 = 1573

Hence,

The rule for given sequence is: a_n = -27+16n

And the 100th term is: 1573

6 0
3 years ago
HELP ILL GIVE BRAINLIEST AND THANKS
tamaranim1 [39]

Answer:

B. -14

Step-by-step explanation:

sana maka tulong ako sayo

at ano ba ang grade nyo

5 0
3 years ago
Pls solve for # 5-8 <br> Thanks
MatroZZZ [7]
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A toy shop purchases 125 identical stuffed animals for a total cost of $312.50 and sells them for $7 each. What is the percent m
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