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3 years ago

Pls help asap

Physics

2 answers:

RoseWind [281]3 years ago

8 0

I’m pretty sure the answer is a

Ira Lisetskai [31]3 years ago

3 0

Answer:

Explanation:

i took lots of time on the lesson

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How are reflecting telescopes similar to devices that produce laser light?

Novosadov [1.4K]

Answer:a

Explanation:

Because its light

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3 years ago

How are stars important to the Milky Way

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Stars are a source of light and heat. They recycle all the matter, gas, and dust and process them into new material. They were created as a major driving force of evolution of the universe.

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Read 2 more answers

A hot-air balloon is descending at a rate of 2.1 m/s when a passenger drops a camera. If the camera is 42 m above the ground whe

zysi [14]

Answer:

a) 2.7s

b) 29 m/s

Explanation:

The equation for the velocity and position of a free fall are the following

$v=v_{0}-gt$ -(1)

$x=x_{0}+v_{0}t-gt^{2}/2$ - (2)

Since the hot-air ballon is <em>descending </em>at 2.1m/s and the camera is dropped at 42 m above the ground:

$v_{0}=-2.1m/s$

$x_{0}=42m$

To calculate the time which it takes to reach the ground we use eq(2) with x=0, and look for the positive solution of t:

$t = \frac{1}{84}(2.1\pm\sqrt{2.1^{2} - 4\times42\times9.81/2} )$

t = 2.71996

Rounding to two significant figures:

t = 2.7 s

Now we calculate the velocity the camera had just before it lands using eq(1) with t=2.7s

$v=-2.1-9.81*(2.71996)$

v = -28.782 m/s

Rounding to two significant figures:

v = -29 m/s

where the minus sign indicates the downwards direction

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3 years ago

a blank is the small number to the lower right of the chemical symbol. It tells how many atoms of the element are present in the

victus00 [196]

The answer is subscript

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4 years ago

Assume that a uniform magnetic field is directed into thispage. If an electron is released with an initial velocity directedfrom

Feliz [49]

Answer:

B). to the right

Explanation:

Since the direction of magnetic field is into the page

So here we know that

$B = B_o(-\hat k)$

now the velocity is from bottom to top

so we have

$v = v_o \hat j$

now the force on the moving charge is given as

$\vec F = q(\vec v \times \vec B)$

now we have

$\vec F = (-e)(v_o \hat j \times B_o(-\hat k))$

$\vec F = e v_o B \hat i$

so force will be towards Right

7 0

3 years ago