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Sergeeva-Olga [200]
2 years ago
13

Pls help asap

Physics
2 answers:
RoseWind [281]2 years ago
8 0
I’m pretty sure the answer is a
Ira Lisetskai [31]2 years ago
3 0

Answer:

D

Explanation:

i took lots of time on the lesson

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3 years ago
In one contest at the county fair, a spring-loaded plunger launches a ball at a speed of 3.2m/s from one corner of a smooth, fla
lara31 [8.8K]

Answer:

Explanation:

Given

Speed of ball u=3.2\ m/s

Plane is inclined at an angle 20^{\circ}

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Launch angle of ball \theta

Motion of ball can be considered in two planes i.e. Vertical to the plane and horizontal to the plane

So Net acceleration in vertical plane is g\sin 20

Range of Projectile is given by

R=\frac{u^2\sin 2\theta }{g}

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2.4=\frac{3.2^2\times sin 2\theta }{g\sin 20}

\sin 2\theta =\frac{2.4\times 9.8\times \sin 20}{3.2^2}

\sin 2\theta =0.7855

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\theta =25.88^{\circ}

so ball must be launched at an angle of 25.88^{\circ}

4 0
3 years ago
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