All categories

3 years ago

What happens during destructive interference?

Physics

1 answer:

Masteriza [31]3 years ago

3 0

They will subtract to form a combined wave with a lower amplitude

You might be interested in

What are the dates of the atlantic hurricane season

Bad White [126]

Answer:

Starts on Saturday, June 1

and ends on

Saturday, November 30

Explanation:

6 0

3 years ago

Read 2 more answers

Which of the answer choices best describes the property of volume? the amount of space a substance's matter occupies the amount

vova2212 [387]

Answer:

amount of space occupied

4 0

3 years ago

Define these terms about speed and state their units<br> speed<br>distance covered<br>time taken

Neporo4naja [7]

Explanation:

Speed is the rate of change of distance with time. It is a scalar quantity with magnitude both no direction.

Speed = $\frac{distance}{time}$

The unit is m/s or km/hr or mile/hr

Distance covered is simply the length of the path traveled.

The unit is m or km or miles

Time taken is the duration of an event.

The unit is seconds or minutes or hour.

4 0

3 years ago

You travel down the highway at a steady rate of 75 mph (33.53 m/s) for a total of 25 minutes, calculate how far you traveled i

Dima020 [189]

Answer:

50280 meters

Explanation:

33.52 meters/seconds is 2011.2 meters/minutes (multiply by 60)

2011.2 meters/m * 25 minutes = answer

3 0

3 years ago

A planet of mass m 6.75 x 1024 kg is orbiting in a circular path a star of mass M 2.75 x 1029 kg. The radius of the orbit is R 8

Umnica [9.8K]

Answer:

The orbital period of the planet is 387.62 days.

Explanation:

Given that,

Mass of planet $m =6.75\times10^{24}\ kg$

Mass of star $m'=2.75\times10^{29}\ kg$

Radius of the orbit $r =8.05\times10^{7}\ km$

Using centripetal and gravitational force

The centripetal force is given by

$F = \dfrac{mv^2}{r}$

$F=m\omega^2r$

We know that,

$\omega=\dfrac{2\pi}{T}$

$F=m(\dfrac{2\pi}{T})^2r$ ....(I)

The gravitational force is given by

$F = \dfrac{mm'G}{r^2}$ ....(II)

From equation (I) and (II)

$m(\dfrac{2\pi}{T})^2r=\dfrac{mm'G}{r^2}$

Where, m = mass of planet

m' = mass of star

G = gravitational constant

r = radius of the orbit

T = time period

Put the value into the formula

$T^2=\dfrac{4\pi^2R^3}{m'G}$

$T^2=\dfrac{4\times(3.14)^2\times(8.05\times10^{7})^3}{2.75\times10^{29}\times6.67\times10^{-11}}$

$T=2\times3.14\times\sqrt{\dfrac{(8.05\times10^{10})^3}{2.75\times10^{29}\times6.67\times10^{-11}}}$

$T =3.34\times10^{7}\ s$

$T= 387.62\days$

Hence, The orbital period of the planet is 387.62 days.

4 0

3 years ago

Read 2 more answers